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Sagot :
To find [tex]\( f(6) \)[/tex] for the function [tex]\( f(x) = 2x^2 + 5\sqrt{x - 2} \)[/tex], follow these steps:
1. Substitute [tex]\( x = 6 \)[/tex] into the function:
[tex]\[ f(6) = 2(6)^2 + 5\sqrt{6 - 2} \][/tex]
2. Calculate [tex]\( (6)^2 \)[/tex]:
[tex]\[ (6)^2 = 36 \][/tex]
3. Multiply [tex]\( 2 \)[/tex] by [tex]\( 36 \)[/tex]:
[tex]\[ 2 \times 36 = 72 \][/tex]
4. Calculate [tex]\( 6 - 2 \)[/tex]:
[tex]\[ 6 - 2 = 4 \][/tex]
5. Find the square root of [tex]\( 4 \)[/tex]:
[tex]\[ \sqrt{4} = 2 \][/tex]
6. Multiply [tex]\( 5 \)[/tex] by [tex]\( 2 \)[/tex]:
[tex]\[ 5 \times 2 = 10 \][/tex]
7. Add the two results together:
[tex]\[ 72 + 10 = 82 \][/tex]
Therefore, [tex]\( f(6) = 82 \)[/tex].
1. Substitute [tex]\( x = 6 \)[/tex] into the function:
[tex]\[ f(6) = 2(6)^2 + 5\sqrt{6 - 2} \][/tex]
2. Calculate [tex]\( (6)^2 \)[/tex]:
[tex]\[ (6)^2 = 36 \][/tex]
3. Multiply [tex]\( 2 \)[/tex] by [tex]\( 36 \)[/tex]:
[tex]\[ 2 \times 36 = 72 \][/tex]
4. Calculate [tex]\( 6 - 2 \)[/tex]:
[tex]\[ 6 - 2 = 4 \][/tex]
5. Find the square root of [tex]\( 4 \)[/tex]:
[tex]\[ \sqrt{4} = 2 \][/tex]
6. Multiply [tex]\( 5 \)[/tex] by [tex]\( 2 \)[/tex]:
[tex]\[ 5 \times 2 = 10 \][/tex]
7. Add the two results together:
[tex]\[ 72 + 10 = 82 \][/tex]
Therefore, [tex]\( f(6) = 82 \)[/tex].
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