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What is the formula for manganese (IV) oxide?

A. [tex]$MnO_4$[/tex]
B. [tex]$Mn_4O$[/tex]
C. [tex]$MnO_2$[/tex]
D. [tex]$Mn_2O$[/tex]

Sagot :

GinnyAnsweridn
To determine the formula for manganese (IV) oxide, we need to consider the typical oxidation states of the elements involved.

1. Identify the oxidation state of manganese (IV):
- Manganese (IV) indicates that manganese has an oxidation state of +4.

2. Identify the oxidation state of oxygen:
- Oxygen typically has an oxidation state of -2.

3. Combine the ions in a way that the total charge is neutral:
- Let’s denote manganese as [tex]\( \text{Mn}^{4+} \)[/tex]
- Let’s denote oxygen as [tex]\( \text{O}^{2-} \)[/tex]

4. Balance the charges:
- Since manganese has a charge of +4 and oxygen has a charge of -2, we need two oxygen atoms to balance the charge of one manganese atom.
- Therefore, one manganese (IV) ion combines with two oxygen ions to form a neutral compound.

5. Write the formula:
- Since one manganese ion combines with two oxygen ions, the formula for manganese (IV) oxide is [tex]\( \text{MnO}_2 \)[/tex].

Hence, the correct chemical formula for manganese (IV) oxide is:
[tex]\[ \boxed{\text{MnO}_2} \][/tex]
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