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What is the internal ratio for S in [tex]\( \text{Al}_2\text{S}_3 \)[/tex]?

A. [tex]\( \frac{3 \text{ mol S}}{6.02 \times 10^{23} \text{ fun Al}_2\text{S}_3} \)[/tex]

B. [tex]\( \frac{1 \text{ mole } \text{S}_3}{1 \text{ mole } \text{Al}_2\text{S}_3} \)[/tex]

C. [tex]\( \frac{3 \text{ mole S}}{1 \text{ mole } \text{Al}_2\text{S}_3} \)[/tex]

Sagot :

GinnyAnsweridn
To find the internal ratio for sulfur (S) in aluminum sulfide ([tex]\(Al_2S_3\)[/tex]), follow these steps:

1. Understand the Formula:
The chemical formula [tex]\(Al_2S_3\)[/tex] tells us that there are 2 moles of aluminum (Al) and 3 moles of sulfur (S) in one mole of [tex]\(Al_2S_3\)[/tex].

2. Identify the Mole Ratios:
- From the chemical formula, the number of moles of S in one mole of [tex]\(Al_2S_3\)[/tex] is 3.
- The number of moles of [tex]\(Al_2S_3\)[/tex] is 1.

3. Calculate the Internal Ratio:
- To find the internal ratio of sulfur to [tex]\(Al_2S_3\)[/tex], take the number of moles of sulfur and divide it by the number of moles of [tex]\(Al_2S_3\)[/tex].

The ratio is:
[tex]\[ \text{Internal Ratio} = \frac{\text{moles of } S}{\text{moles of } Al_2S_3} = \frac{3}{1} = 3.0 \][/tex]

Therefore, the internal ratio for [tex]\(S\)[/tex] in [tex]\(Al_2S_3\)[/tex] is 3.0. This means there are 3 moles of sulfur for every 1 mole of [tex]\(Al_2S_3\)[/tex].
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