Answered

IDNLearn.com is your go-to platform for finding reliable answers quickly. Our platform is designed to provide reliable and thorough answers to all your questions, no matter the topic.

Which equation demonstrates that nuclear fusion forms elements that are heavier than helium?

A. [tex]\( {}_1^2 H + {}_1^3 H \longrightarrow {}_2^4 He + {}_0^1 n \)[/tex]
B. [tex]\( {}_8^{16} O + {}_2^4 He \longrightarrow {}_{10}^{20} Ne \)[/tex]
C. [tex]\( {}_{92}^{235} U + {}_0^1 n \longrightarrow {}_{53}^{131} I + {}_{39}^{89} Y + 160_0^1 n \)[/tex]
D. [tex]\( {}_{92}^{235} U + {}_0^1 n \longrightarrow {}_{42}^{95} Mo + {}_{57}^{139} La + 2{}_0^1 n + 7_{-1}^0 e \)[/tex]

Sagot :

GinnyAnsweridn
To determine which equation demonstrates that nuclear fusion forms elements that are heavier than helium, let's carefully consider each reaction.

1. [tex]\(\ce{^2_1H + ^3_1H -> ^4_2He + ^1_0n}\)[/tex]:

- This reaction involves deuterium ([tex]\(\ce{^2_1H}\)[/tex]) and tritium ([tex]\(\ce{^3_1H}\)[/tex]), which are both isotopes of hydrogen.
- These two hydrogen nuclei combine (fusion) to form a helium nucleus ([tex]\(\ce{^4_2He}\)[/tex]) and a neutron ([tex]\(\ce{^1_0n}\)[/tex]).

While this is a fusion reaction, helium is not heavier than helium since the output is just helium and a neutron.

2. [tex]\(\ce{^16_8O + ^4_2He -> ^20_{10}Ne}\)[/tex]:

- This reaction involves an oxygen nucleus ([tex]\(\ce{^16_8O}\)[/tex]) and a helium nucleus ([tex]\(\ce{^4_2He}\)[/tex]).
- These nuclei combine (fusion) to form a neon nucleus ([tex]\(\ce{^20_{10}Ne}\)[/tex]).

This is a fusion reaction that results in the formation of neon, an element that is heavier than helium.

3. [tex]\(\ce{^235_{92}U + ^1_0n -> ^131_{53}I + ^89_{39}Y + 16 ^1_0n}\)[/tex]:

- This reaction involves uranium-235 ([tex]\(\ce{^235_{92}U}\)[/tex]) and a neutron ([tex]\(\ce{^1_0n}\)[/tex]).
- The uranium nucleus undergoes fission, splitting into iodine ([tex]\(\ce{^131_{53}I}\)[/tex]) and yttrium ([tex]\(\ce{^89_{39}Y}\)[/tex]), along with multiple neutrons.

This is a fission reaction, not a fusion reaction.

4. [tex]\(\ce{^235_{92}U + ^1_0n -> ^95_{42}Mo + ^139_{57}La + 2 ^1_0n + 7 ^0_{-1}e}\)[/tex]:

- This reaction also involves uranium-235 ([tex]\(\ce{^235_{92}U}\)[/tex]) and a neutron ([tex]\(\ce{^1_0n}\)[/tex]).
- The uranium nucleus again undergoes fission, resulting in the formation of molybdenum ([tex]\(\ce{^95_{42}Mo}\)[/tex]) and lanthanum ([tex]\(\ce{^139_{57}La}\)[/tex]), along with several neutrons and electrons.

This is another example of a fission reaction, not a fusion reaction.

Based on the analysis, the equation that demonstrates nuclear fusion forming an element that is heavier than helium is:
[tex]\[ \ce{^16_8O + ^4_2He -> ^20_{10}Ne} \][/tex]

Therefore, the correct answer is the second equation.
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.