IDNLearn.com connects you with a community of experts ready to answer your questions. Our platform is designed to provide reliable and thorough answers to all your questions, no matter the topic.
Sagot :
To rationalize the denominator of the expression [tex]\(\frac{6 x^4}{\sqrt{7 x+12}}\)[/tex], we follow these steps:
1. Start with the given expression:
[tex]\[ \frac{6 x^4}{\sqrt{7 x + 12}} \][/tex]
2. Multiply both the numerator and the denominator by the conjugate of the denominator, which in this case is [tex]\(\sqrt{7 x + 12}\)[/tex]. This step helps us eliminate the square root in the denominator:
[tex]\[ \frac{6 x^4}{\sqrt{7 x + 12}} \cdot \frac{\sqrt{7 x + 12}}{\sqrt{7 x + 12}} \][/tex]
3. Simplify the expression:
The numerator becomes:
[tex]\[ 6 x^4 \cdot \sqrt{7 x + 12} \][/tex]
The denominator becomes:
[tex]\[ \sqrt{7 x + 12} \cdot \sqrt{7 x + 12} = 7 x + 12 \][/tex]
4. Putting it all together, we get:
[tex]\[ \frac{6 x^4 \cdot \sqrt{7 x + 12}}{7 x + 12} \][/tex]
So, the rationalized form of the expression [tex]\(\frac{6 x^4}{\sqrt{7 x + 12}}\)[/tex] is:
[tex]\[ \frac{6 x^4 \sqrt{7 x + 12}}{7 x + 12} \][/tex]
1. Start with the given expression:
[tex]\[ \frac{6 x^4}{\sqrt{7 x + 12}} \][/tex]
2. Multiply both the numerator and the denominator by the conjugate of the denominator, which in this case is [tex]\(\sqrt{7 x + 12}\)[/tex]. This step helps us eliminate the square root in the denominator:
[tex]\[ \frac{6 x^4}{\sqrt{7 x + 12}} \cdot \frac{\sqrt{7 x + 12}}{\sqrt{7 x + 12}} \][/tex]
3. Simplify the expression:
The numerator becomes:
[tex]\[ 6 x^4 \cdot \sqrt{7 x + 12} \][/tex]
The denominator becomes:
[tex]\[ \sqrt{7 x + 12} \cdot \sqrt{7 x + 12} = 7 x + 12 \][/tex]
4. Putting it all together, we get:
[tex]\[ \frac{6 x^4 \cdot \sqrt{7 x + 12}}{7 x + 12} \][/tex]
So, the rationalized form of the expression [tex]\(\frac{6 x^4}{\sqrt{7 x + 12}}\)[/tex] is:
[tex]\[ \frac{6 x^4 \sqrt{7 x + 12}}{7 x + 12} \][/tex]
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Find clear answers at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.