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A 43.40 mg sample of an alcohol contains 15.10 mg of O, 22.60 mg of C, and 5.70 mg of H. What is its percent composition of hydrogen?

Sagot :

Let's find the percent composition of hydrogen in the given sample.

The problem provides the following masses:
- Total mass of the alcohol sample: [tex]\( 43.40 \, \text{mg} \)[/tex]
- Mass of hydrogen ([tex]\( H \)[/tex]): [tex]\( 5.70 \, \text{mg} \)[/tex]

To find the percent composition of hydrogen, we follow these steps:

1. Identify the total mass of the sample: [tex]\( 43.40 \, \text{mg} \)[/tex].

2. Identify the mass of hydrogen in the sample: [tex]\( 5.70 \, \text{mg} \)[/tex].

3. Calculate the percent composition of hydrogen using the formula:
[tex]\[ \text{Percent composition of } H = \left( \frac{\text{Mass of } H}{\text{Total mass of the sample}} \right) \times 100 \][/tex]

Plugging in the given values:
[tex]\[ \text{Percent composition of } H = \left( \frac{5.70}{43.40} \right) \times 100 \][/tex]

4. Evaluate the expression:
[tex]\[ \left( \frac{5.70}{43.40} \right) \times 100 \approx 13.133640552995393 \][/tex]

Therefore, the percent composition of hydrogen in the sample is approximately [tex]\( 13.133640552995393\% \)[/tex].