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The endpoints of [tex]\(\overline{WX}\)[/tex] are [tex]\(W (2, -7)\)[/tex] and [tex]\(X (5, -4)\)[/tex].

What is the length of [tex]\(\overline{WX}\)[/tex]?

A. 3
B. 6
C. 18
D. [tex]\(\sqrt{6}\)[/tex]
E. [tex]\(3\sqrt{2}\)[/tex]


Sagot :

To determine the length of the line segment [tex]\(\overline{WX}\)[/tex] with endpoints [tex]\(W(2, -7)\)[/tex] and [tex]\(X(5, -4)\)[/tex], we use the distance formula:

[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]

Here, [tex]\((x_1, y_1)\)[/tex] are the coordinates of point [tex]\(W\)[/tex] and [tex]\((x_2, y_2)\)[/tex] are the coordinates of point [tex]\(X\)[/tex].

Given:
- [tex]\( W(2, -7) = (x_1, y_1) \)[/tex]
- [tex]\( X(5, -4) = (x_2, y_2) \)[/tex]

Substitute the coordinates into the distance formula:
[tex]\[ d = \sqrt{(5 - 2)^2 + (-4 + 7)^2} \][/tex]

Calculate each squared difference:

1. The difference in [tex]\( x\)[/tex] coordinates: [tex]\( 5 - 2 = 3 \)[/tex]
- Squaring this difference: [tex]\( 3^2 = 9 \)[/tex]

2. The difference in [tex]\( y \)[/tex] coordinates: [tex]\( -4 + 7 = 3 \)[/tex]
- Squaring this difference: [tex]\( 3^2 = 9 \)[/tex]

Add the squared differences:
[tex]\[ 9 + 9 = 18 \][/tex]

Take the square root of the sum:
[tex]\[ d = \sqrt{18} \][/tex]

Since [tex]\( \sqrt{18} \)[/tex] can be simplified further:
[tex]\[ \sqrt{18} = \sqrt{9 \times 2} = 3\sqrt{2} \][/tex]

Thus, the length of [tex]\(\overline{WX}\)[/tex] is:
[tex]\[ \boxed{3 \sqrt{2}} \][/tex]

Therefore, the correct answer is [tex]\( \boxed{E} \)[/tex].