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If two gases with pressures of 2 atm and 3 atm are mixed at a constant temperature, what will the total pressure be?

A. 2 atm + 3 atm
B. 3 atm - 2 atm
C. [tex]\(\frac{2 \text{ atm} + 3 \text{ atm}}{2}\)[/tex]
D. 2 atm [tex]\(\times\)[/tex] 3 atm


Sagot :

Sure, let's work through this problem step-by-step.

When two gases are mixed at a constant temperature, the total pressure exerted by the mixture of gases in a container can be found using Dalton's Law of Partial Pressures. According to Dalton's Law, the total pressure exerted by a mixture of non-reacting gases is equal to the sum of the partial pressures of the individual gases.

Here are the pressures of the two given gases:
- Pressure of gas 1: [tex]\( 2 \, \text{atm} \)[/tex]
- Pressure of gas 2: [tex]\( 3 \, \text{atm} \)[/tex]

To find the total pressure when these gases are mixed, we sum the pressures of the two gases:
[tex]\[ \text{Total Pressure} = \text{Pressure of gas 1} + \text{Pressure of gas 2} \][/tex]

Substituting in the values:
[tex]\[ \text{Total Pressure} = 2 \, \text{atm} + 3 \, \text{atm} \][/tex]

Performing the addition:
[tex]\[ \text{Total Pressure} = 5 \, \text{atm} \][/tex]

So the correct answer to the question, using the choices provided, is:

A. [tex]\( 2 \, \text{atm} + 3 \, \text{atm} \)[/tex]

As this correctly states the operation to find the total pressure of the gas mixture.