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Unattached earlobes are dominant to attached earlobes. Cleft chin is dominant to no cleft. Parents that are heterozygous for both traits are crossed.

Determine the genotype of the following offspring.

| | EA | Ea | eA | ea |
|-----|-----|-----|-----|-----|
| EA | EEAA | EEAa | EeAA | EeAa |
| Ea | EEAa | EeAa | EeAa | Eeaa |
| eA | EeAA | EeAa | eeAA | eeAa |
| ea | EeAa | Eeaa | eeAa | eeaa |

Offspring genotypes:

1. EeAa
2. EEAa
3. EeAa
4. EeAA
5. eeAa


Sagot :

To determine the genotypes of the offspring from the given Punnett square, we first need to fill in the blanks in the table by following the Mendelian inheritance rules for a dihybrid cross (where both parents are heterozygous for both traits).

The specific parents' genotypes are:
- Both parents have the genotype "EeAa".

The possible gametes formed by these parents are:
- EA, Ea, eA, ea.

Let’s fill in the table based on the cross of these gametes:

Here’s the detailed step-by-step solution:

1. EA x EA = EEAA (already provided in table)
2. EA x Ea = EEAa (already provided in table)
3. EA x eA = EeAA (already provided in table)
4. EA x ea = EeAa (already provided in table)

Moving on to the next row:

5. Ea x EA = EEAa (already provided in table)
6. Ea x Ea = EEaa
7. Ea x eA = EeAa (already provided in table)
8. Ea x ea = Eeaa (already provided in table)

Continuing to the next row:

9. eA x EA = EeAA (already provided in table)
10. eA x Ea = EeAa (already provided in table)
11. eA x eA = eeAA
12. eA x ea = eeAa (already provided in table)

For the last row:

13. ea x EA = EeAa (already provided in table)
14. ea x Ea = Eeaa (already provided in table)
15. ea x eA = eeAa (already provided in table)
16. ea x ea = eeaa (already provided in table)

Now, we’ll extract the genotypes of the specific positions indicated in your question.

1. EeAa (Already given)
2. From first row, second column: EEAa (EA x Ea)
3. From first column, second row: EeAA (Ea x EA)
4. From second column, third row: EeAa (eA x Ea)
5. From last row, last column: eeaa (ea x ea)

So the genotypes of the offspring in the specified positions are:

1. EeAa
2. EEAa
3. EeAA
4. EeAa
5. eeaa

All positions are now defined as:
[tex]\[ \begin{tabular}{|c|c|c|c|} \hline EA & Ea & eA & ea \\ \hline EEAA & EEAa & EeAA & EeAa \\ \hline EEAa & EEaa & EeAa & Eeaa \\ \hline EeAA & EeAa & eeAA & eeAa \\ \hline EeAa & Eeaa & eeAa & eeaa \\ \hline \end{tabular} \][/tex]

Note that genotypes corresponding to position numbers are:

1. EeAa [tex]\(\sim\)[/tex]
2. EEAa
3. EeAA
4. EeAa
5. eeaa