Connect with knowledgeable experts and enthusiasts on IDNLearn.com. Our platform provides detailed and accurate responses from experts, helping you navigate any topic with confidence.
Sagot :
We are asked to find a polynomial that has [tex]\(5\)[/tex] as its root. Let's follow the steps to arrive at the correct polynomial equation clearly.
1. Identify the Root and Form the Factor:
- Given that the solution set contains the number [tex]\(5\)[/tex], this means [tex]\(5\)[/tex] is a root of the polynomial.
- Therefore, [tex]\((x - 5)\)[/tex] is a factor of the polynomial.
2. Form a Quadratic Polynomial:
- For simplicity, we can consider the case where the polynomial is of degree 2 (a quadratic polynomial).
- The polynomial can be expressed as the square of the linear factor: [tex]\((x - 5)^2\)[/tex].
3. Expand the Polynomial:
- To expand [tex]\((x - 5)^2\)[/tex], use the binomial expansion formula: [tex]\((a - b)^2 = a^2 - 2ab + b^2\)[/tex].
- Substituting [tex]\(a = x\)[/tex] and [tex]\(b = 5\)[/tex]:
[tex]\[ (x - 5)^2 = x^2 - 2 \cdot x \cdot 5 + 5^2 \][/tex]
- Simplify the expression:
[tex]\[ (x - 5)^2 = x^2 - 10x + 25 \][/tex]
4. Verify the Form:
- We have now found that the expanded form of [tex]\((x - 5)^2\)[/tex] results in the quadratic polynomial:
[tex]\[ x^2 - 10x + 25 \][/tex]
5. Select the Correct Answer:
- Now match the expanded form with the available options:
[tex]\[ \begin{array}{l} x^2 - 5x + 25 = 0 \\ x^2 + 10x + 25 = 0 \\ x^2 - 10x + 25 = 0 \\ x^2 + 5x + 25 = 0 \end{array} \][/tex]
- The polynomial that matches [tex]\(x^2 - 10x + 25\)[/tex] is the correct one.
Thus, the correct polynomial equation for which [tex]\(\{5\}\)[/tex] is the solution set is:
[tex]\[ x^{\wedge} 2-10 x+25 = 0 \][/tex]
1. Identify the Root and Form the Factor:
- Given that the solution set contains the number [tex]\(5\)[/tex], this means [tex]\(5\)[/tex] is a root of the polynomial.
- Therefore, [tex]\((x - 5)\)[/tex] is a factor of the polynomial.
2. Form a Quadratic Polynomial:
- For simplicity, we can consider the case where the polynomial is of degree 2 (a quadratic polynomial).
- The polynomial can be expressed as the square of the linear factor: [tex]\((x - 5)^2\)[/tex].
3. Expand the Polynomial:
- To expand [tex]\((x - 5)^2\)[/tex], use the binomial expansion formula: [tex]\((a - b)^2 = a^2 - 2ab + b^2\)[/tex].
- Substituting [tex]\(a = x\)[/tex] and [tex]\(b = 5\)[/tex]:
[tex]\[ (x - 5)^2 = x^2 - 2 \cdot x \cdot 5 + 5^2 \][/tex]
- Simplify the expression:
[tex]\[ (x - 5)^2 = x^2 - 10x + 25 \][/tex]
4. Verify the Form:
- We have now found that the expanded form of [tex]\((x - 5)^2\)[/tex] results in the quadratic polynomial:
[tex]\[ x^2 - 10x + 25 \][/tex]
5. Select the Correct Answer:
- Now match the expanded form with the available options:
[tex]\[ \begin{array}{l} x^2 - 5x + 25 = 0 \\ x^2 + 10x + 25 = 0 \\ x^2 - 10x + 25 = 0 \\ x^2 + 5x + 25 = 0 \end{array} \][/tex]
- The polynomial that matches [tex]\(x^2 - 10x + 25\)[/tex] is the correct one.
Thus, the correct polynomial equation for which [tex]\(\{5\}\)[/tex] is the solution set is:
[tex]\[ x^{\wedge} 2-10 x+25 = 0 \][/tex]
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.