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Find the polynomial.

{5} is the solution set of ______________ .

A. [tex]\(x^2 - 5x + 25 = 0\)[/tex]
B. [tex]\(x^2 + 10x + 25 = 0\)[/tex]
C. [tex]\(x^2 - 10x + 25 = 0\)[/tex]
D. [tex]\(x^2 + 5x + 25 = 0\)[/tex]


Sagot :

We are asked to find a polynomial that has [tex]\(5\)[/tex] as its root. Let's follow the steps to arrive at the correct polynomial equation clearly.

1. Identify the Root and Form the Factor:
- Given that the solution set contains the number [tex]\(5\)[/tex], this means [tex]\(5\)[/tex] is a root of the polynomial.
- Therefore, [tex]\((x - 5)\)[/tex] is a factor of the polynomial.

2. Form a Quadratic Polynomial:
- For simplicity, we can consider the case where the polynomial is of degree 2 (a quadratic polynomial).
- The polynomial can be expressed as the square of the linear factor: [tex]\((x - 5)^2\)[/tex].

3. Expand the Polynomial:
- To expand [tex]\((x - 5)^2\)[/tex], use the binomial expansion formula: [tex]\((a - b)^2 = a^2 - 2ab + b^2\)[/tex].
- Substituting [tex]\(a = x\)[/tex] and [tex]\(b = 5\)[/tex]:
[tex]\[ (x - 5)^2 = x^2 - 2 \cdot x \cdot 5 + 5^2 \][/tex]
- Simplify the expression:
[tex]\[ (x - 5)^2 = x^2 - 10x + 25 \][/tex]

4. Verify the Form:
- We have now found that the expanded form of [tex]\((x - 5)^2\)[/tex] results in the quadratic polynomial:
[tex]\[ x^2 - 10x + 25 \][/tex]

5. Select the Correct Answer:
- Now match the expanded form with the available options:
[tex]\[ \begin{array}{l} x^2 - 5x + 25 = 0 \\ x^2 + 10x + 25 = 0 \\ x^2 - 10x + 25 = 0 \\ x^2 + 5x + 25 = 0 \end{array} \][/tex]
- The polynomial that matches [tex]\(x^2 - 10x + 25\)[/tex] is the correct one.

Thus, the correct polynomial equation for which [tex]\(\{5\}\)[/tex] is the solution set is:
[tex]\[ x^{\wedge} 2-10 x+25 = 0 \][/tex]