Explore a vast range of topics and get informed answers at IDNLearn.com. Ask anything and receive immediate, well-informed answers from our dedicated community of experts.
Sagot :
Sure, let's start by analyzing the given information and then complete the table step-by-step.
From the problem, we know that the amount earned by each worker, [tex]\( A \)[/tex], varies inversely with the number of workers, [tex]\( n \)[/tex]. This relationship is expressed as:
[tex]\[ A = \frac{k}{n} \][/tex]
where [tex]\( k \)[/tex] is a constant. Given that the total labor budget is \[tex]$25,000, this constant \( k \) can be determined by the equation when \( n = 1 \): \[ k = 25,000 \] This constant implies that for any number of workers \( n \), the total amount earned by each worker \( A \) times the number of workers \( n \) would always equal \$[/tex]25,000.
Now let's complete the table using the inverse relationship [tex]\( A = \frac{25,000}{n} \)[/tex].
\begin{tabular}{c|c}
[tex]$n$[/tex] & A \\
\hline
1 & 25,000 \\
\hline
2 & 12,500 \\
\hline
3 & \frac{25,000}{3} \approx 8333.33 \\
\hline
5 & \frac{25,000}{5} = 5,000 \\
\hline
10 & \frac{25,000}{10} = 2,500 \\
\hline
25 & \frac{25,000}{25} = 1,000 \\
\hline
50 & \frac{25,000}{50} = 500 \\
\hline
\end{tabular}
Here is the completed table:
\begin{tabular}{c|c}
[tex]$n$[/tex] & A \\
\hline
1 & 25,000 \\
\hline
2 & 12,500 \\
\hline
3 & 8,333.33 \\
\hline
5 & 5,000 \\
\hline
10 & 2,500 \\
\hline
25 & 1,000 \\
\hline
50 & 500 \\
\hline
\end{tabular}
Now, for the second part of the question: we notice that the product [tex]\( A \cdot n \)[/tex] should always equal the total budget, which is \[tex]$25,000. Let's verify this for each entry in the table: - For \( n = 1 \), \( A = 25,000 \), so \( A \cdot n = 25,000 \cdot 1 = 25,000 \) - For \( n = 2 \), \( A = 12,500 \), so \( A \cdot n = 12,500 \cdot 2 = 25,000 \) - For \( n = 3 \), \( A = 8,333.33 \), so \( A \cdot n = 8,333.33 \cdot 3 \approx 25,000 \) - For \( n = 5 \), \( A = 5,000 \), so \( A \cdot n = 5,000 \cdot 5 = 25,000 \) - For \( n = 10 \), \( A = 2,500 \), so \( A \cdot n = 2,500 \cdot 10 = 25,000 \) - For \( n = 25 \), \( A = 1,000 \), so \( A \cdot n = 1,000 \cdot 25 = 25,000 \) - For \( n = 50 \), \( A = 500 \), so \( A \cdot n = 500 \cdot 50 = 25,000 \) Hence, we observe that the product \( A \cdot n \) is indeed constant and equals \$[/tex]25,000 for all values of [tex]\( n \)[/tex].
From the problem, we know that the amount earned by each worker, [tex]\( A \)[/tex], varies inversely with the number of workers, [tex]\( n \)[/tex]. This relationship is expressed as:
[tex]\[ A = \frac{k}{n} \][/tex]
where [tex]\( k \)[/tex] is a constant. Given that the total labor budget is \[tex]$25,000, this constant \( k \) can be determined by the equation when \( n = 1 \): \[ k = 25,000 \] This constant implies that for any number of workers \( n \), the total amount earned by each worker \( A \) times the number of workers \( n \) would always equal \$[/tex]25,000.
Now let's complete the table using the inverse relationship [tex]\( A = \frac{25,000}{n} \)[/tex].
\begin{tabular}{c|c}
[tex]$n$[/tex] & A \\
\hline
1 & 25,000 \\
\hline
2 & 12,500 \\
\hline
3 & \frac{25,000}{3} \approx 8333.33 \\
\hline
5 & \frac{25,000}{5} = 5,000 \\
\hline
10 & \frac{25,000}{10} = 2,500 \\
\hline
25 & \frac{25,000}{25} = 1,000 \\
\hline
50 & \frac{25,000}{50} = 500 \\
\hline
\end{tabular}
Here is the completed table:
\begin{tabular}{c|c}
[tex]$n$[/tex] & A \\
\hline
1 & 25,000 \\
\hline
2 & 12,500 \\
\hline
3 & 8,333.33 \\
\hline
5 & 5,000 \\
\hline
10 & 2,500 \\
\hline
25 & 1,000 \\
\hline
50 & 500 \\
\hline
\end{tabular}
Now, for the second part of the question: we notice that the product [tex]\( A \cdot n \)[/tex] should always equal the total budget, which is \[tex]$25,000. Let's verify this for each entry in the table: - For \( n = 1 \), \( A = 25,000 \), so \( A \cdot n = 25,000 \cdot 1 = 25,000 \) - For \( n = 2 \), \( A = 12,500 \), so \( A \cdot n = 12,500 \cdot 2 = 25,000 \) - For \( n = 3 \), \( A = 8,333.33 \), so \( A \cdot n = 8,333.33 \cdot 3 \approx 25,000 \) - For \( n = 5 \), \( A = 5,000 \), so \( A \cdot n = 5,000 \cdot 5 = 25,000 \) - For \( n = 10 \), \( A = 2,500 \), so \( A \cdot n = 2,500 \cdot 10 = 25,000 \) - For \( n = 25 \), \( A = 1,000 \), so \( A \cdot n = 1,000 \cdot 25 = 25,000 \) - For \( n = 50 \), \( A = 500 \), so \( A \cdot n = 500 \cdot 50 = 25,000 \) Hence, we observe that the product \( A \cdot n \) is indeed constant and equals \$[/tex]25,000 for all values of [tex]\( n \)[/tex].
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.