IDNLearn.com is your reliable source for expert answers and community insights. Discover prompt and accurate answers from our community of experienced professionals.
Sagot :
To determine the level of the atmosphere where the rocket will be after one minute, let's break down the problem step-by-step.
1. Time Conversion: Understand that the given time is one minute. Converting this into seconds, since there are 60 seconds in a minute:
[tex]\[ \text{Time} = 1 \, \text{minute} \times 60 \, \text{seconds/minute} = 60 \, \text{seconds} \][/tex]
2. Rocket Speed: Assume a typical speed of a rocket shortly after launch, which is 7.8 km/s.
3. Distance Calculation: Calculate the distance traveled by the rocket in those 60 seconds.
[tex]\[ \text{Distance} = \text{Speed} \times \text{Time} = 7.8 \, \text{km/s} \times 60\, \text{seconds} = 468 \, \text{km} \][/tex]
4. Determine the Atmospheric Level: Based on the given altitude ranges in the table, check where 468 km falls:
[tex]\[ \begin{array}{|c|c|} \text{Stratosphere} & 12-50 \, \text{km} \\ \hline \text{Mesosphere} & 50-80 \, \text{km} \\ \hline \text{Thermosphere} & 50-440 \, \text{km} \\ \hline \text{Exosphere} & > 440 \, \text{km} \\ \hline \end{array} \][/tex]
The calculated distance of 468 km exceeds 440 km. Therefore, the rocket is in the Exosphere.
So, the correct answer is:
A. Exosphere
1. Time Conversion: Understand that the given time is one minute. Converting this into seconds, since there are 60 seconds in a minute:
[tex]\[ \text{Time} = 1 \, \text{minute} \times 60 \, \text{seconds/minute} = 60 \, \text{seconds} \][/tex]
2. Rocket Speed: Assume a typical speed of a rocket shortly after launch, which is 7.8 km/s.
3. Distance Calculation: Calculate the distance traveled by the rocket in those 60 seconds.
[tex]\[ \text{Distance} = \text{Speed} \times \text{Time} = 7.8 \, \text{km/s} \times 60\, \text{seconds} = 468 \, \text{km} \][/tex]
4. Determine the Atmospheric Level: Based on the given altitude ranges in the table, check where 468 km falls:
[tex]\[ \begin{array}{|c|c|} \text{Stratosphere} & 12-50 \, \text{km} \\ \hline \text{Mesosphere} & 50-80 \, \text{km} \\ \hline \text{Thermosphere} & 50-440 \, \text{km} \\ \hline \text{Exosphere} & > 440 \, \text{km} \\ \hline \end{array} \][/tex]
The calculated distance of 468 km exceeds 440 km. Therefore, the rocket is in the Exosphere.
So, the correct answer is:
A. Exosphere
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.