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A plant can have either broad leaves (B) or narrow leaves (b). A plant with genotype BB is crossed with a plant with genotype Bb. Which Punnett square correctly represents this cross?

A.
\begin{tabular}{|c|c|c|}
\hline & b & b \\
\hline & Bb & Bb \\
\hline & bb & bb \\
\hline
\end{tabular}

B.
\begin{tabular}{|c|c|}
\multicolumn{1}{c}{} & \multicolumn{1}{|c|}{b} \\
\hline B & Bb \\
\hline B & Bb \\
\hline
\end{tabular}

C.
\begin{tabular}{|c|c|c|}
\hline & B & b \\
\hline B & Bb & Bb \\
\hline B & Bb & Bb \\
\hline
\end{tabular}

D.
\begin{tabular}{|c|c|c|}
\hline & B & b \\
\hline B & BB & Bb \\
\hline B & BB & Bb \\
\hline
\end{tabular}

Sagot :

GinnyAnsweridn
To determine which Punnett Square correctly represents the cross between a plant with genotype [tex]\(BB\)[/tex] and a plant with genotype [tex]\(Bb\)[/tex], we must first understand how the alleles combine.

1. Parents' Genotypes:
- One parent has genotype [tex]\(BB\)[/tex]
- The other parent has genotype [tex]\(Bb\)[/tex]

2. Gametes Produced:
- The BB parent can only contribute [tex]\(B\)[/tex] alleles.
- The Bb parent can contribute either [tex]\(B\)[/tex] or [tex]\(b\)[/tex] alleles.

3. Construct the Punnett Square:

The setup for the Punnett square would look like this:

[tex]\[ \begin{array}{c|c|c} & B & b \\ \hline B & BB & Bb \\ \hline B & BB & Bb \\ \end{array} \][/tex]

Each cell in the Punnett square represents a possible combination of alleles from each parent. The possible genotypes of the offspring are:

- Upper left cell: [tex]\(BB\)[/tex]
- Upper right cell: [tex]\(Bb\)[/tex]
- Lower left cell: [tex]\(BB\)[/tex]
- Lower right cell: [tex]\(Bb\)[/tex]

4. Evaluate Given Options:

Option A:
[tex]\[ \begin{array}{|c|c|c|} \hline & b & b \\ \hline & Bb & Bb \\ \hline & bb & bb \\ \hline \end{array} \][/tex]
- This option incorrectly includes [tex]\(bb\)[/tex] genotypes, which are not possible from a cross of [tex]\(BB \times Bb\)[/tex].

Option B:
[tex]\[ \begin{array}{|c|c|} \multicolumn{1}{c}{} & \multicolumn{1}{|c|}{} \\ \hline B & b \\ \hline BB & Bb \\ \hline BB & Bb \\ \hline \end{array} \][/tex]
- This option correctly represents the possible offspring genotypes: [tex]\(BB\)[/tex] and [tex]\(Bb\)[/tex].

Option C:
[tex]\[ \begin{array}{|c|c|c|} \hline & B & b \\ \hline & Bb & Bb \\ \hline & Bb & Br \\ \hline \end{array} \][/tex]
- This option incorrectly includes a genotype [tex]\(Br\)[/tex], which is not valid with the given alleles.

Option D:
[tex]\[ \begin{array}{|c|c|c|} \hline & B & b \\ \hline & BB & Bb \\ \hline 0 & BB & Bb \\ \hline \end{array} \][/tex]
- This option incorrectly includes a genotype 0, which is not valid.

Therefore, the correct representation of this cross in a Punnett Square is:

Option B:
[tex]\[ \begin{array}{|c|c|} \multicolumn{1}{c}{} & \multicolumn{1}{|c|}{} \\ \hline B & b \\ \hline BB & Bb \\ \hline BB & Bb \\ \hline \end{array} \][/tex]

The correct option is 2.
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