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What is the molar mass of this compound?

[tex]\[ Zn \left( C_2 H_3 O_2 \right)_2 \][/tex]

A. 94.43 g/mol
B. 183.48 g/mol
C. 189.87 g/mol
D. 154.46 g/mol

Remember to round to the hundredths place from the periodic table.

Sagot :

GinnyAnsweridn
To determine the molar mass of the compound [tex]\( \text{Zn}\left(\text{C}_2\text{H}_3\text{O}_2\right)_2 \)[/tex], we need to sum the molar masses of all the atoms present in the compound. Here is a step-by-step calculation:

1. Identify the elements and their respective quantities within the compound:

- The chemical formula [tex]\( \text{Zn}\left(\text{C}_2\text{H}_3\text{O}_2\right)_2 \)[/tex] consists of:
- 1 Zinc (Zn)
- 2 groups of [tex]\( \text{C}_2\text{H}_3\text{O}_2 \)[/tex]

2. Find the atomic mass of each element from the periodic table and round to hundredths:

- [tex]\( \text{Zn} \)[/tex] (Zinc): 65.38 g/mol
- [tex]\( \text{C} \)[/tex] (Carbon): 12.01 g/mol
- [tex]\( \text{H} \)[/tex] (Hydrogen): 1.01 g/mol
- [tex]\( \text{O} \)[/tex] (Oxygen): 16.00 g/mol

3. Calculate the molar mass of one [tex]\( \text{C}_2\text{H}_3\text{O}_2 \)[/tex] group:

- [tex]\( 2 \times \text{C} \)[/tex] = [tex]\( 2 \times 12.01 \)[/tex] g/mol = 24.02 g/mol
- [tex]\( 3 \times \text{H} \)[/tex] = [tex]\( 3 \times 1.01 \)[/tex] g/mol = 3.03 g/mol
- [tex]\( 2 \times \text{O} \)[/tex] = [tex]\( 2 \times 16.00 \)[/tex] g/mol = 32.00 g/mol

Total for [tex]\( \text{C}_2\text{H}_3\text{O}_2 \)[/tex] = 24.02 g/mol + 3.03 g/mol + 32.00 g/mol = 59.05 g/mol

4. Since there are two [tex]\( \text{C}_2\text{H}_3\text{O}_2 \)[/tex] groups in the compound, multiply the molar mass by 2:

- 2 \times 59.05 g/mol = 118.10 g/mol

5. Add the molar mass of Zinc (Zn):

- [tex]\( 118.10 \)[/tex] g/mol (from two [tex]\( \text{C}_2\text{H}_3\text{O}_2 \)[/tex] groups) + [tex]\( 65.38 \)[/tex] g/mol (for Zn)

6. Combine the molar masses to get the total molar mass of the compound:

- 118.10 g/mol + 65.38 g/mol = 183.48 g/mol

Therefore, the molar mass of [tex]\( \text{Zn}\left(\text{C}_2\text{H}_3\text{O}_2\right)_2 \)[/tex] is 183.48 g/mol. The correct answer among the options given is:
[tex]\[ \boxed{183.48 \, \text{g/mol}} \][/tex]
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