Join IDNLearn.com and start getting the answers you've been searching for. Discover detailed and accurate answers to your questions from our knowledgeable and dedicated community members.

How many formula units are in 35.0 g of KNO₃?

(Molar mass of KNO₃ = 101.11 g/mol)

[tex]\[ \text{[?]} \times 10^{[?]} \text{ formula units of KNO₃} \][/tex]


Sagot :

To determine the number of formula units in 35.0 grams of [tex]\( \text{KNO}_3 \)[/tex], follow these steps:

1. Determine the number of moles of [tex]\( \text{KNO}_3 \)[/tex]:

The molar mass of [tex]\( \text{KNO}_3 \)[/tex] is given as 101.11 g/mol.

Using the formula for moles (number of moles = mass / molar mass):
[tex]\[ \text{moles} = \frac{35.0 \text{ g}}{101.11 \text{ g/mol}} \approx 0.3462 \text{ moles} \][/tex]

2. Convert moles to formula units using Avogadro's number:

Avogadro's number ([tex]\(6.022 \times 10^{23}\)[/tex]) tells us how many entities (atoms, molecules, formula units, etc.) are in one mole of a substance.

To find the number of formula units:
[tex]\[ \text{formula units} = \text{moles} \times \text{Avogadro's number} \][/tex]
Substituting the values:
[tex]\[ \text{formula units} = 0.3462 \text{ moles} \times 6.022 \times 10^{23} \approx 2.08 \times 10^{23} \text{ formula units} \][/tex]

So, in 35.0 grams of [tex]\( \text{KNO}_3 \)[/tex], there are approximately [tex]\(2.08 \times 10^{23}\)[/tex] formula units of [tex]\( \text{KNO}_3 \)[/tex].