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The pOH of a solution is 10.75. What is the concentration of [tex]\( OH^{-} \)[/tex] ions in the solution?

Use [tex]\( \left[ OH^{-} \right] = 10^{-pOH} \)[/tex].

A. [tex]\( 3.162 \times 10^{-108} \)[/tex] M
B. [tex]\( 1.778 \times 10^{-11} \)[/tex] M
C. [tex]\( 1.075 \times 10^2 \)[/tex] M
D. [tex]\( 5.623 \times 10^{10} \)[/tex] M

Sagot :

GinnyAnsweridn
To determine the concentration of hydroxide ions (OH⁻) from the given pOH value, follow these steps:

1. Understand the formula:
The relationship between pOH and the concentration of OH⁻ ions is given by the formula:
[tex]\[ [OH^-] = 10^{-pOH} \][/tex]

2. Substitute the given pOH value:
We have a pOH of 10.75. Substitute 10.75 into the formula:
[tex]\[ [OH^-] = 10^{-10.75} \][/tex]

3. Calculate the result:
Evaluating [tex]\(10^{-10.75}\)[/tex] gives us the concentration of hydroxide ions. Therefore:
[tex]\[ [OH^-] = 1.7782794100389227 \times 10^{-11} M \][/tex]
This is the scientific notation of the concentration, which can also be simplified to:
[tex]\[ [OH^-] \approx 1.778 \times 10^{-11} M \][/tex]

Thus, among the given options, the correct answer is:
[tex]\[ 1.778 \times 10^{-11} M \][/tex]
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