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Order the steps to solve the equation [tex]\(\log \left(x^2 - 15\right) = \log (2x)\)[/tex] from 1 to 5.

[tex]\(\square\)[/tex] [tex]\(x^2 - 15 = 2x\)[/tex]

[tex]\(\square\)[/tex] [tex]\(x^2 - 2x - 15 = 0\)[/tex]

[tex]\(\square\)[/tex]
[tex]\[
(x-5)(x+3) = 0 \\
x-5 = 0 \text{ or } x+3 = 0
\][/tex]

[tex]\(\square\)[/tex] Potential solutions are -3 and 5

Sagot :

GinnyAnsweridn
Certainly! Here are the steps ordered to solve the equation [tex]\(\log \left(x^2-15\right)=\log (2 x)\)[/tex]:

1. [tex]\(\boxed{x^2-15=2 x}\)[/tex]
2. [tex]\(\boxed{x^2-2 x-15=0}\)[/tex]
3. [tex]\(\boxed{(x-5)(x+3)=0}\)[/tex]
4. [tex]\(\boxed{x-5=0 \text { or } x+3=0}\)[/tex]
5. [tex]\(\boxed{Potential solutions are -3 and 5}\)[/tex]

This is the correct order from start to finish in solving the given equation.
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