Connect with a community that values knowledge and expertise on IDNLearn.com. Ask your questions and receive detailed and reliable answers from our experienced and knowledgeable community members.

Explain which variables in the periodic function must be modified in order to cut the amplitude in half and how this would modify the equation.

The initial equation is [tex][tex]$f(x)=A \sin (B x-C)+D$[/tex][/tex].

(3 marks)


Sagot :

To cut the amplitude of the sine function [tex]\( f(x) = A \sin (Bx - C) + D \)[/tex] in half, we need to focus on the coefficient [tex]\( A \)[/tex], as it directly determines the amplitude of the function. The amplitude of a sine function [tex]\( f(x) \)[/tex] is given by the absolute value of [tex]\( A \)[/tex].

Let's outline the steps involved in modifying the equation to achieve the desired amplitude reduction:

1. Identify the initial amplitude:
The initial amplitude of the function is [tex]\( A \)[/tex].

2. Calculate the new amplitude:
To cut the amplitude in half, we simply divide the initial amplitude [tex]\( A \)[/tex] by 2.
[tex]\[ \text{New Amplitude} = \frac{A}{2} \][/tex]

3. Modify the equation:
With the new amplitude being [tex]\( \frac{A}{2} \)[/tex], we substitute this value into the original function in place of [tex]\( A \)[/tex]. Therefore, the modified equation becomes:
[tex]\[ f(x) = \left(\frac{A}{2}\right) \sin (Bx - C) + D \][/tex]

So, the variables in the initial equation that must be modified are specifically the amplitude [tex]\( A \)[/tex]. After the adjustment, the modified equation is:
[tex]\[ f(x) = \frac{A}{2} \sin (Bx - C) + D \][/tex]

This modified equation ensures that the amplitude of the sine function is now half of its original value.