Join IDNLearn.com today and start getting the answers you've been searching for. Find the solutions you need quickly and accurately with help from our knowledgeable community.

1. Find two more terms in each sequence:

(a) [tex]1, 2, 3, 4, \ldots[/tex]
(b) [tex]5, 10, 15, 20, 25, \ldots[/tex]
(c) [tex]2, 4, 6, 8, 10, \ldots[/tex]
(d) [tex]22, 20, 18, 16, 14, \ldots[/tex]
(e) [tex]1, 2, 4, 8, 16, \ldots[/tex]
(f) [tex]2, 5, 9, 14, 20, \ldots[/tex]
(g) [tex]-8, -6, -4, \ldots[/tex]
(h) [tex]\frac{1}{3}, \frac{4}{5}, \frac{7}{7}, \frac{10}{9}, \ldots[/tex]

2. Find the general term [tex]t_n[/tex] of the following sequences:

(a) [tex]4, 6, 8, 10, \ldots[/tex]
(b) [tex]7, 11, 15, 19, 23, \ldots[/tex]
(c) [tex]2, 6, 10, 14, 18, \ldots[/tex]
(d) [tex]25, 22, 19, 16, \ldots[/tex]
(e) [tex]\frac{1}{3}, \frac{4}{5}, \frac{7}{7}, \frac{10}{9}, \ldots[/tex]
(f) [tex]\frac{2}{7}, \frac{5}{8}, \frac{8}{9}, \frac{11}{10}, \ldots[/tex]
(g) [tex]40, 38, 36, 34, \ldots[/tex]
(h) [tex]\frac{2}{5}, \frac{4}{8}, \frac{6}{11}, \frac{8}{14}, \ldots[/tex]


Sagot :

Let's address each part of the question step-by-step.

### Part 1: Finding Two More Terms

#### (a) Sequence: [tex]\(1, 2, 3, 4, \ldots\)[/tex]
The given sequence increases by 1 each time.
- Next two terms: [tex]\(5, 6\)[/tex]

So, the sequence becomes: [tex]\(1, 2, 3, 4, 5, 6\)[/tex]

#### (b) Sequence: [tex]\(5, 10, 15, 20, 25, \ldots\)[/tex]
The given sequence increases by 5 each time.
- Next two terms: [tex]\(30, 35\)[/tex]

So, the sequence becomes: [tex]\(5, 10, 15, 20, 25, 30, 35\)[/tex]

#### (c) Sequence: [tex]\(2, 4, 6, 8, 10, \ldots\)[/tex]
The given sequence increases by 2 each time.
- Next two terms: [tex]\(12, 14\)[/tex]

So, the sequence becomes: [tex]\(2, 4, 6, 8, 10, 12, 14\)[/tex]

#### (d) Sequence: [tex]\(22, 20, 18, 16, 14, \ldots\)[/tex]
The given sequence decreases by 2 each time.
- Next two terms: [tex]\(12, 10\)[/tex]

So, the sequence becomes: [tex]\(22, 20, 18, 16, 14, 12, 10\)[/tex]

#### (e) Sequence: [tex]\(1, 2, 4, 8, 16, \ldots\)[/tex]
The given sequence is multiplied by 2 each time.
- Next two terms: [tex]\(32, 64\)[/tex]

So, the sequence becomes: [tex]\(1, 2, 4, 8, 16, 32, 64\)[/tex]

#### (f) Sequence: [tex]\(2, 5, 9, 14, 20, \ldots\)[/tex]
The given sequence increases by increments of 3, 4, 5, ...
- Next two terms: [tex]\(27, 35\)[/tex]

So, the sequence becomes: [tex]\(2, 5, 9, 14, 20, 27, 35\)[/tex]

#### (g) Sequence: [tex]\(-8, -6, -4, \ldots\)[/tex]
The given sequence increases by 2 each time.
- Next two terms: [tex]\(-2, 0\)[/tex]

So, the sequence becomes: [tex]\(-8, -6, -4, -2, 0\)[/tex]

#### (h) Sequence: [tex]\(\frac{1}{3}, \frac{4}{5}, \frac{7}{7}, \frac{10}{9}, \ldots\)[/tex]
Identifying the terms does not appear straightforward, but using the provided result:
- Next two terms: [tex]\(\frac{13}{11}, \frac{16}{13}\)[/tex]

So, the sequence becomes: [tex]\(\frac{1}{3}, \frac{4}{5}, \frac{7}{7}, \frac{10}{9}, \frac{13}{11}, \frac{16}{13}\)[/tex]

### Part 2: General Terms [tex]\( t_n \)[/tex]

Let's determine the general term for each sequence.

#### (a) Sequence: [tex]\(4, 6, 8, 10, \ldots\)[/tex]
This is an arithmetic sequence with a common difference of 2 and a first term of 4.
[tex]\[ t_n = 2n + 2 \][/tex]

#### (b) Sequence: [tex]\(7, 11, 15, 19, 23, \ldots\)[/tex]
This is an arithmetic sequence with a common difference of 4 and a first term of 7.
[tex]\[ t_n = 4n + 3 \][/tex]

#### (c) Sequence: [tex]\(2, 6, 10, 14, 18, \ldots\)[/tex]
This is an arithmetic sequence with a common difference of 4 and a first term of 2.
[tex]\[ t_n = 4n - 2 \][/tex]

#### (d) Sequence: [tex]\(25, 22, 19, 16, \ldots\)[/tex]
This is an arithmetic sequence with a common difference of -3 and a first term of 25.
[tex]\[ t_n = 28 - 3n \][/tex]

#### (e) Sequence: [tex]\(\frac{1}{3}, \frac{4}{5}, \frac{7}{7}, \frac{10}{9}, \ldots\)[/tex]
The general term cannot be determined as a simple arithmetic or geometric sequence.
[tex]\[ t_n = \text{Cannot be determined as a simple arithmetic or geometric sequence} \][/tex]

#### (f) Sequence: [tex]\(\frac{2}{7}, \frac{5}{8}, \frac{8}{9}, \frac{11}{10}, \ldots\)[/tex]
The general term cannot be determined as a simple arithmetic or geometric sequence.
[tex]\[ t_n = \text{Cannot be determined as a simple arithmetic or geometric sequence} \][/tex]

#### (g) Sequence: [tex]\(40, 38, 36, 34, \ldots\)[/tex]
This is an arithmetic sequence with a common difference of -2 and a first term of 40.
[tex]\[ t_n = 42 - 2n \][/tex]

#### (h) Sequence: [tex]\(\frac{2}{5}, \frac{4}{8}, \frac{6}{11}, \frac{8}{14}, \ldots\)[/tex]
The general term cannot be determined as a simple arithmetic or geometric sequence.
[tex]\[ t_n = \text{Cannot be determined as a simple arithmetic or geometric sequence} \][/tex]

This concludes our detailed solution.