From simple queries to complex problems, IDNLearn.com provides reliable answers. Our Q&A platform offers reliable and thorough answers to help you make informed decisions quickly and easily.

A square is inscribed in a circle of diameter [tex][tex]$12 \sqrt{2}$[/tex][/tex] millimeters. What is the area of the shaded region?

Recall that in a [tex][tex]$45^{\circ}-45^{\circ}-90^{\circ}$[/tex][/tex] triangle, if the legs each measure [tex][tex]$x$[/tex][/tex] units, then the hypotenuse measures [tex][tex]$x \sqrt{2}$[/tex][/tex] units.

A. [tex][tex]$(72 \pi - 144) \text{ mm}^2$[/tex][/tex]
B. [tex][tex]$(72 \pi - 72) \text{ mm}^2$[/tex][/tex]
C. [tex][tex]$(288 \pi - 288) \text{ mm}^2$[/tex][/tex]
D. [tex][tex]$(288 \pi - 144) \text{ mm}^2$[/tex][/tex]


Sagot :

To determine the area of the shaded region formed by a square inscribed in a circle, we need to follow these steps:

1. Determine the diameter of the circle:

Given in the problem, the diameter of the circle is [tex]\( 12\sqrt{2} \)[/tex] millimeters.

2. Find the side length of the square:

Since the square is inscribed in the circle, the diagonal of the square is equal to the diameter of the circle. In a 45°-45°-90° triangle (which forms half of the square), if the legs each measure [tex]\( x \)[/tex] units, then the hypotenuse measures [tex]\( x\sqrt{2} \)[/tex]. Here, the hypotenuse [tex]\( x\sqrt{2} \)[/tex] is the diagonal of the square and is equal to the diameter of the circle:
[tex]\[ x\sqrt{2} = 12\sqrt{2} \implies x = 12 \][/tex]
Therefore, the side length of the square is [tex]\( 12 \)[/tex] millimeters.

3. Calculate the area of the square:

The area of the square is given by the side length squared:
[tex]\[ \text{Area of the square} = 12^2 = 144 \text{ mm}^2 \][/tex]

4. Calculate the radius of the circle:

The radius of the circle is half of its diameter:
[tex]\[ \text{Radius} = \frac{12\sqrt{2}}{2} = 6\sqrt{2} \text{ mm} \][/tex]

5. Calculate the area of the circle:

The area of the circle is given by:
[tex]\[ \text{Area of the circle} = \pi \times (\text{Radius})^2 = \pi \times (6\sqrt{2})^2 = \pi \times 72 = 72\pi \text{ mm}^2 \][/tex]

6. Determine the area of the shaded region:

The shaded region is the area of the circle minus the area of the square:
[tex]\[ \text{Area of the shaded region} = 72\pi \text{ mm}^2 - 144 \text{ mm}^2 \][/tex]

Therefore, the area of the shaded region is [tex]\( 72\pi - 144 \text{ mm}^2 \)[/tex].

Thus, the answer is [tex]\((72\pi - 144) \text{ mm}^2\)[/tex].
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.