Sure, let's break down the given arithmetic expression step by step:
[tex]\[
\begin{array}{l}
1+1+1+1 \\
+1+1+1+ \\
1+1+1+1 \\
+1 \times 0 + 1 = ?
\end{array}
\][/tex]
First, we need to handle the multiplication operation first, as per the order of operations (PEMDAS/BODMAS).
So, the term [tex]\(1 \times 0\)[/tex] needs to be calculated first:
[tex]\[
1 \times 0 = 0
\][/tex]
Next, we substitute this result back into the original expression:
[tex]\[
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1
\][/tex]
Now, we sum up all the remaining terms:
[tex]\[
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1
\][/tex]
Let's count the number of ones and zeros in the expression. The expression consists of twelve 1's and one 0. Adding these together:
[tex]\[
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1 = 12
\][/tex]
Therefore, the result of the expression is:
[tex]\[
\boxed{12}
\][/tex]
