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log base 5 of 12.5+ log base five of 2​

Sagot :

Answer:

2

Step-by-step explanation:

[tex] \log_b x + \log_b y = \log_b xy [/tex]

[tex] \log_5 12.5 + \log_5 2 = \log_5 25 = 2 [/tex]

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