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What is the simplified base of the function [tex][tex]$f(x)=\frac{1}{4}(\sqrt[3]{108})^x$[/tex][/tex]?

A. 3
B. [tex][tex]$3 \sqrt[3]{4}$[/tex][/tex]
C. [tex][tex]$6 \sqrt[3]{3}$[/tex][/tex]
D. 27


Sagot :

To determine the simplified base of the function [tex]\( f(x) = \frac{1}{4} (\sqrt[3]{108})^x \)[/tex], let's proceed step-by-step:

1. Calculate the cube root of 108:
[tex]\[ \sqrt[3]{108} \approx 4.762203155904598 \][/tex]

2. Express 108 as a product of prime factors:
[tex]\[ 108 = 2^2 \cdot 3^3 \][/tex]

3. Find the cube root of 108 in terms of its prime factors:
[tex]\[ \sqrt[3]{108} = \sqrt[3]{2^2 \cdot 3^3} \][/tex]
This can be broken down as:
[tex]\[ \sqrt[3]{2^2} = 2^{2/3} \][/tex]
and
[tex]\[ \sqrt[3]{3^3} = 3 \][/tex]
Therefore,
[tex]\[ \sqrt[3]{108} = 2^{2/3} \cdot 3 \][/tex]

4. Simplify the base of the function:
[tex]\[ \text{Base} = \frac{1}{4} \sqrt[3]{108} \][/tex]
Substitute [tex]\(\sqrt[3]{108}\)[/tex] with its simplified form:
[tex]\[ \text{Base} = \frac{1}{4} (2^{2/3} \cdot 3) \][/tex]

5. Combine and simplify the expression:
[tex]\[ \text{Base} = \frac{1}{4} \cdot 2^{2/3} \cdot 3 \][/tex]
Since [tex]\(\frac{1}{4} = 2^{-2}\)[/tex], we can write:
[tex]\[ \text{Base} = 2^{-2} \cdot 2^{2/3} \cdot 3 = 2^{2/3 - 2} \cdot 3 \][/tex]
Simplifying [tex]\(2^{2/3 - 2}\)[/tex]:
[tex]\[ 2^{2/3 - 2} = 2^{2/3 - 6/3} = 2^{-4/3} \][/tex]
So,
[tex]\[ \text{Base} = 2^{-4/3} \cdot 3 \][/tex]

6. Converting the base to a decimal form:
Using the numerical result, we have:
[tex]\[ 2^{-4/3} \cdot 3 \approx 0.520020955762976 \][/tex]

Therefore, the simplified base of the function [tex]\( f(x) = \frac{1}{4} (\sqrt[3]{108})^x \)[/tex] is approximately [tex]\( 0.520020955762976 \)[/tex]. This results from a combination of the cube root of 108 and the fraction [tex]\(\frac{1}{4}\)[/tex].