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Sagot :
To determine the slope of a linear function represented by the coordinates in a table, we use the formula for the slope [tex]\( m \)[/tex], which is given by:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Given the values from the table:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 0 & 5 \\ \hline 4 & 9 \\ \hline \end{array} \][/tex]
We can identify the points as [tex]\((x_1, y_1) = (0, 5)\)[/tex] and [tex]\((x_2, y_2) = (4, 9)\)[/tex].
Plugging these values into the slope formula, we get:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{9 - 5}{4 - 0} \][/tex]
Calculating the numerator and the denominator separately:
[tex]\[ 9 - 5 = 4 \quad \text{and} \quad 4 - 0 = 4 \][/tex]
So the slope [tex]\( m \)[/tex] is:
[tex]\[ m = \frac{4}{4} = 1 \][/tex]
Therefore, the correct expression that can be used to determine the slope of the linear function represented in the table is:
[tex]\[ \frac{9-5}{4-0} \][/tex]
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Given the values from the table:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 0 & 5 \\ \hline 4 & 9 \\ \hline \end{array} \][/tex]
We can identify the points as [tex]\((x_1, y_1) = (0, 5)\)[/tex] and [tex]\((x_2, y_2) = (4, 9)\)[/tex].
Plugging these values into the slope formula, we get:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{9 - 5}{4 - 0} \][/tex]
Calculating the numerator and the denominator separately:
[tex]\[ 9 - 5 = 4 \quad \text{and} \quad 4 - 0 = 4 \][/tex]
So the slope [tex]\( m \)[/tex] is:
[tex]\[ m = \frac{4}{4} = 1 \][/tex]
Therefore, the correct expression that can be used to determine the slope of the linear function represented in the table is:
[tex]\[ \frac{9-5}{4-0} \][/tex]
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