Discover new knowledge and insights with IDNLearn.com's extensive Q&A database. Join our community to receive prompt and reliable responses to your questions from experienced professionals.
Sagot :
To simplify the expression [tex]\(\sqrt[4]{567 x^9 y^{11}}\)[/tex], we will use properties of rational exponents step-by-step. Here is the correct order of the simplification steps:
1. Rewrite the given expression using rational exponents:
[tex]\[ \left(567 x^9 y^{11}\right)^{\frac{1}{4}} \][/tex]
2. Factor the expression inside the parenthesis. Since [tex]\(567 = 81 \cdot 7\)[/tex] and [tex]\(81 = 3^4\)[/tex], we get:
[tex]\[ (3^4 \cdot 7 \cdot x^9 \cdot y^{11})^{\frac{1}{4}} \][/tex]
3. Apply the exponentiation rule to each factor inside the parenthesis:
[tex]\[ \left(3^4\right)^{\frac{1}{4}} \cdot 7^{\frac{1}{4}} \cdot x^{\frac{9}{4}} \cdot y^{\frac{11}{4}} \][/tex]
4. Simplify [tex]\(\left(3^4\right)^{\frac{1}{4}}\)[/tex] to 3 and leave the others as they are:
[tex]\[ 3 \cdot 7^{\frac{1}{4}} \cdot x^{\frac{9}{4}} \cdot y^{\frac{11}{4}} \][/tex]
5. Rewrite the exponents of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] by breaking them down:
[tex]\[ 3 \cdot x^2 \cdot y^2 \cdot 7^{\frac{1}{4}} \cdot x^{\frac{1}{4}} \cdot y^{\frac{3}{4}} \][/tex]
6. Combine the terms having the same [tex]\( \frac{1}{4} \)[/tex] exponent:
[tex]\[ 3 x^2 y^2 \left( 7 x y^3 \right)^{\frac{1}{4}} \][/tex]
7. Rewrite the expression using radical notation:
[tex]\[ 3 x^2 y^2 \sqrt[4]{7 x y^3} \][/tex]
Therefore, the ordered steps are as follows:
1. [tex]\(\left(567 x^9 y^{11}\right)^{\frac{1}{4}}\)[/tex]
2. [tex]\((3^4 \cdot 7 \cdot x^9 \cdot y^{11})^{\frac{1}{4}}\)[/tex]
3. [tex]\(\left(3^4\right)^{\frac{1}{4}} \cdot 7^{\frac{1}{4}} \cdot x^{\frac{9}{4}} \cdot y^{\frac{11}{4}}\)[/tex]
4. [tex]\(3 \cdot 7^{\frac{1}{4}} \cdot x^{\frac{9}{4}} \cdot y^{\frac{11}{4}}\)[/tex]
5. [tex]\(3 \cdot x^2 \cdot y^2 \cdot\left(7^{\frac{1}{4}} \cdot x^{\frac{1}{4}} \cdot y^{\frac{3}{4}}\right)\)[/tex]
6. [tex]\(3 x^2 y^2 \cdot\left(7 x y^3\right)^{\frac{1}{4}}\)[/tex]
7. [tex]\(3 x^2 y^2 \sqrt[4]{7 x y^3}\)[/tex]
Each step builds on the previous one to progressively simplify the initial expression.
1. Rewrite the given expression using rational exponents:
[tex]\[ \left(567 x^9 y^{11}\right)^{\frac{1}{4}} \][/tex]
2. Factor the expression inside the parenthesis. Since [tex]\(567 = 81 \cdot 7\)[/tex] and [tex]\(81 = 3^4\)[/tex], we get:
[tex]\[ (3^4 \cdot 7 \cdot x^9 \cdot y^{11})^{\frac{1}{4}} \][/tex]
3. Apply the exponentiation rule to each factor inside the parenthesis:
[tex]\[ \left(3^4\right)^{\frac{1}{4}} \cdot 7^{\frac{1}{4}} \cdot x^{\frac{9}{4}} \cdot y^{\frac{11}{4}} \][/tex]
4. Simplify [tex]\(\left(3^4\right)^{\frac{1}{4}}\)[/tex] to 3 and leave the others as they are:
[tex]\[ 3 \cdot 7^{\frac{1}{4}} \cdot x^{\frac{9}{4}} \cdot y^{\frac{11}{4}} \][/tex]
5. Rewrite the exponents of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] by breaking them down:
[tex]\[ 3 \cdot x^2 \cdot y^2 \cdot 7^{\frac{1}{4}} \cdot x^{\frac{1}{4}} \cdot y^{\frac{3}{4}} \][/tex]
6. Combine the terms having the same [tex]\( \frac{1}{4} \)[/tex] exponent:
[tex]\[ 3 x^2 y^2 \left( 7 x y^3 \right)^{\frac{1}{4}} \][/tex]
7. Rewrite the expression using radical notation:
[tex]\[ 3 x^2 y^2 \sqrt[4]{7 x y^3} \][/tex]
Therefore, the ordered steps are as follows:
1. [tex]\(\left(567 x^9 y^{11}\right)^{\frac{1}{4}}\)[/tex]
2. [tex]\((3^4 \cdot 7 \cdot x^9 \cdot y^{11})^{\frac{1}{4}}\)[/tex]
3. [tex]\(\left(3^4\right)^{\frac{1}{4}} \cdot 7^{\frac{1}{4}} \cdot x^{\frac{9}{4}} \cdot y^{\frac{11}{4}}\)[/tex]
4. [tex]\(3 \cdot 7^{\frac{1}{4}} \cdot x^{\frac{9}{4}} \cdot y^{\frac{11}{4}}\)[/tex]
5. [tex]\(3 \cdot x^2 \cdot y^2 \cdot\left(7^{\frac{1}{4}} \cdot x^{\frac{1}{4}} \cdot y^{\frac{3}{4}}\right)\)[/tex]
6. [tex]\(3 x^2 y^2 \cdot\left(7 x y^3\right)^{\frac{1}{4}}\)[/tex]
7. [tex]\(3 x^2 y^2 \sqrt[4]{7 x y^3}\)[/tex]
Each step builds on the previous one to progressively simplify the initial expression.
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.