Alkaryidn
Answered

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Consider this code:

[tex]\[
\begin{array}{ll}
1 & x = -10 \\
2 & y = \operatorname{abs}(x) \\
3 & x = 11
\end{array}
\][/tex]

(Reminder: the built-in function \textit{abs} returns the absolute value of a number.)

After the code above is executed, what value does [tex]\( y \)[/tex] refer to?

Sagot :

GinnyAnsweridn
Let's analyze the given code step-by-step:

1. The first line of code initializes the variable [tex]\( x \)[/tex] with a value of [tex]\(-10\)[/tex].
[tex]\[ x = -10 \][/tex]

2. The second line of code sets the variable [tex]\( y \)[/tex] to be the absolute value of [tex]\( x \)[/tex]. The absolute value of a number is its non-negative value. Given [tex]\( x = -10 \)[/tex],
[tex]\[ y = \operatorname{abs}(x) = \operatorname{abs}(-10) = 10 \][/tex]

3. The third line of code assigns a new value to [tex]\( x \)[/tex], which is now [tex]\( 11 \)[/tex]. However, this change does not affect the value of [tex]\( y \)[/tex] since [tex]\( y \)[/tex] has already been set to [tex]\( 10 \)[/tex] in the previous step.
[tex]\[ x = 11 \][/tex]

After executing all these steps, the variable [tex]\( y \)[/tex] holds the value [tex]\( 10 \)[/tex]. Therefore, the value referred to by [tex]\( y \)[/tex] is [tex]\( 10 \)[/tex].
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