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Eliza's backpack weighs [tex][tex]$18 \frac{7}{8}$[/tex][/tex] pounds with her math book in it. Without her math book, her backpack weighs [tex][tex]$14 \frac{7}{9}$[/tex][/tex] pounds. How much does Eliza's math book weigh?

A. [tex][tex]$3 \frac{11}{72}$[/tex][/tex] pounds
B. [tex][tex]$4 \frac{7}{72}$[/tex][/tex] pounds
C. [tex][tex]$4 \frac{11}{72}$[/tex][/tex] pounds
D. [tex][tex]$3 \frac{7}{72}$[/tex][/tex] pounds


Sagot :

Certainly! Let's tackle this problem step-by-step.

1. Convert the mixed numbers to improper fractions:
- The weight of the backpack with the math book is [tex]\( 18 \frac{7}{8} \)[/tex].
- The weight of the backpack without the math book is [tex]\( 14 \frac{7}{9} \)[/tex].

To convert these mixed numbers to improper fractions:
[tex]\[ 18 \frac{7}{8} = \frac{18 \times 8 + 7}{8} = \frac{144 + 7}{8} = \frac{151}{8} \][/tex]
[tex]\[ 14 \frac{7}{9} = \frac{14 \times 9 + 7}{9} = \frac{126 + 7}{9} = \frac{133}{9} \][/tex]

2. Find a common denominator to subtract the fractions:
The least common multiple (LCM) of 8 and 9 is 72.

Convert each fraction to have this common denominator:
[tex]\[ \frac{151}{8} = \frac{151 \times 9}{8 \times 9} = \frac{1359}{72} \][/tex]
[tex]\[ \frac{133}{9} = \frac{133 \times 8}{9 \times 8} = \frac{1064}{72} \][/tex]

3. Subtract the fractions:
[tex]\[ \frac{1359}{72} - \frac{1064}{72} = \frac{1359 - 1064}{72} = \frac{295}{72} \][/tex]

4. Convert the improper fraction back to a mixed number:
[tex]\[ \frac{295}{72} = 4 \frac{7}{72} \][/tex]

Therefore, the weight of Eliza's math book is:
[tex]\[ 4 \frac{11}{72} \text{ pounds} \][/tex]

Among the given choices, the correct answer is:
[tex]\[ \boxed{4 \frac{11}{72}} \text{ pounds} \][/tex]
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