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A rotating sprinkler head sprays water as far as 20 feet. The head is set to cover a central angle of [tex]80^{\circ}[/tex]. What area of grass will be watered?

A. [tex]\frac{200}{9} \pi \, \text{ft}^2[/tex]

B. [tex]\frac{760}{9} \pi \, \text{ft}^2[/tex]

C. [tex]\frac{800}{9} \pi \, \text{ft}^2[/tex]

D. [tex]\frac{80}{2} \pi \, \text{ft}^2[/tex]


Sagot :

To determine the area of grass watered by the sprinkler, we need to calculate the area of the sector formed by the central angle [tex]\(80^\circ\)[/tex] with a radius of 20 feet. A sector of a circle is a portion of the circle that resembles a 'slice of pie' and its area can be calculated using the following steps:

1. Convert the Angle to Radians:
The given angle is [tex]\(80^\circ\)[/tex]. To use it in calculations, we need to convert it to radians.

[tex]\[ \text{angle in radians} = 80^\circ \times \frac{\pi}{180^\circ} = \frac{80\pi}{180} = \frac{4\pi}{9} \approx 1.396 \][/tex]

2. Calculate the Area of the Full Circle:
The area [tex]\(A\)[/tex] of a full circle with radius [tex]\(r = 20\)[/tex] feet is given by the formula:

[tex]\[ A_{\text{circle}} = \pi r^2 = \pi (20)^2 = 400\pi \][/tex]

3. Calculate the Area of the Sector:
The area of the sector (portion of the circle covered by the sprinkler) can be determined by the ratio of the central angle to the full circle angle [tex]\(2\pi\)[/tex] radians.

[tex]\[ \text{Area of sector} = \left( \frac{\theta}{2\pi} \right) \times A_{\text{circle}} \][/tex]

Here, [tex]\(\theta = \frac{4\pi}{9}\)[/tex] is the central angle in radians.

[tex]\[ \text{Area of sector} = \left( \frac{\frac{4\pi}{9}}{2\pi} \right) \times 400\pi = \left( \frac{4}{18} \right) \times 400\pi = \frac{2}{9} \times 400\pi = \frac{800}{9} \pi \text{ square feet} \][/tex]

Thus, the correct area of the grass watered by the sprinkler is [tex]\(\frac{800}{9} \pi\)[/tex] square feet. Therefore, the correct answer is:

C. [tex]\(\frac{800}{9} \pi \, \text{ft}^2\)[/tex]
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