Find the best answers to your questions with the help of IDNLearn.com's expert contributors. Our experts provide timely, comprehensive responses to ensure you have the information you need.
Sagot :
To solve this problem, follow these steps:
1. Understand the given ratio: The ratio of flour to sugar is given as 2:1. This means for every 2 parts of flour, there is 1 part of sugar.
2. Identify the given quantity of flour: We are told that 4 cups of flour are used.
3. Set up the ratio relationship: Since the ratio of flour to sugar is 2:1, we know:
[tex]\[ \text{flour} = 2 \times \text{sugar} \][/tex]
4. Substitute the known quantity into the ratio: We know the quantity of flour is 4 cups, so:
[tex]\[ 4 = 2 \times \text{sugar} \][/tex]
5. Solve for the number of cups of sugar: To find the number of cups of sugar, divide both sides of the equation by 2:
[tex]\[ \text{sugar} = \frac{4}{2} \][/tex]
[tex]\[ \text{sugar} = 2 \][/tex]
So, 2 cups of sugar are needed when 4 cups of flour are used.
1. Understand the given ratio: The ratio of flour to sugar is given as 2:1. This means for every 2 parts of flour, there is 1 part of sugar.
2. Identify the given quantity of flour: We are told that 4 cups of flour are used.
3. Set up the ratio relationship: Since the ratio of flour to sugar is 2:1, we know:
[tex]\[ \text{flour} = 2 \times \text{sugar} \][/tex]
4. Substitute the known quantity into the ratio: We know the quantity of flour is 4 cups, so:
[tex]\[ 4 = 2 \times \text{sugar} \][/tex]
5. Solve for the number of cups of sugar: To find the number of cups of sugar, divide both sides of the equation by 2:
[tex]\[ \text{sugar} = \frac{4}{2} \][/tex]
[tex]\[ \text{sugar} = 2 \][/tex]
So, 2 cups of sugar are needed when 4 cups of flour are used.
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.