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Sagot :
To solve this problem, we need to figure out how much Misha spends on oranges and pears and then represent that mathematically as an inequality.
1. Determine the cost of 2 pounds of oranges:
- Oranges cost \[tex]$1.30 per pound. - For 2 pounds, the cost of oranges would be \(2 \times 1.30\). \[ 2 \times 1.30 = 2.60 \] 2. Determine the total amount of money spent: - Misha spends less than \$[/tex]10.00 in total.
3. Determine the amount left for pears:
- Subtract the cost of the oranges from the total money spent.
[tex]\[ 10.00 - 2.60 = 7.40 \][/tex]
4. Determine the inequality for pears:
- Pears cost \$1.90 per pound.
- Let [tex]\(x\)[/tex] be the weight in pounds of pears.
- The cost of pears would be [tex]\(1.90x\)[/tex].
- This cost should be less than the remaining money:
[tex]\[ 1.90x < 7.40 \][/tex]
Therefore, the correct inequality that represents the situation is [tex]\(1.90x < 7.40\)[/tex]. Hence, the best answer among the provided choices is:
[tex]\[ 2(1.30) + 1.90x < 10.00 \][/tex]
1. Determine the cost of 2 pounds of oranges:
- Oranges cost \[tex]$1.30 per pound. - For 2 pounds, the cost of oranges would be \(2 \times 1.30\). \[ 2 \times 1.30 = 2.60 \] 2. Determine the total amount of money spent: - Misha spends less than \$[/tex]10.00 in total.
3. Determine the amount left for pears:
- Subtract the cost of the oranges from the total money spent.
[tex]\[ 10.00 - 2.60 = 7.40 \][/tex]
4. Determine the inequality for pears:
- Pears cost \$1.90 per pound.
- Let [tex]\(x\)[/tex] be the weight in pounds of pears.
- The cost of pears would be [tex]\(1.90x\)[/tex].
- This cost should be less than the remaining money:
[tex]\[ 1.90x < 7.40 \][/tex]
Therefore, the correct inequality that represents the situation is [tex]\(1.90x < 7.40\)[/tex]. Hence, the best answer among the provided choices is:
[tex]\[ 2(1.30) + 1.90x < 10.00 \][/tex]
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