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If [tex]\( f(x) \)[/tex] and [tex]\( f^{-1}(x) \)[/tex] are inverse functions of each other and [tex]\( f(x) = 2x + 5 \)[/tex], what is [tex]\( f^{-1}(8) \)[/tex]?

A. [tex]\(-1\)[/tex]

B. [tex]\(\frac{3}{2}\)[/tex]

C. [tex]\(\frac{41}{8}\)[/tex]

D. 23


Sagot :

To find the inverse function of [tex]\( f(x) = 2x + 5 \)[/tex], we follow these steps:

1. Replace [tex]\( f(x) \)[/tex] with [tex]\( y \)[/tex]:
[tex]\[ y = 2x + 5 \][/tex]

2. Swap [tex]\( x \)[/tex] and [tex]\( y \)[/tex] to solve for the inverse function:
[tex]\[ x = 2y + 5 \][/tex]

3. Solve for [tex]\( y \)[/tex] to find the inverse function:
[tex]\[ x - 5 = 2y \implies y = \frac{x - 5}{2} \][/tex]

Thus, the inverse function is:
[tex]\[ f^{-1}(x) = \frac{x - 5}{2} \][/tex]

Now we need to find [tex]\( f^{-1}(8) \)[/tex]:

4. Substitute [tex]\( x = 8 \)[/tex] into the inverse function:
[tex]\[ f^{-1}(8) = \frac{8 - 5}{2} \][/tex]

5. Simplify the expression:
[tex]\[ f^{-1}(8) = \frac{3}{2} \][/tex]

Therefore, the value of [tex]\( f^{-1}(8) \)[/tex] is [tex]\( \frac{3}{2} \)[/tex]. The correct answer is:

[tex]\[ \boxed{\frac{3}{2}} \][/tex]