To determine the monthly deviation from the average for each of these months, we'll follow a systematic process.
### Step-by-step solution:
1. Understand the Concept of Deviation:
The deviation for a given month is calculated by subtracting the average sales from the actual sales of that month. Mathematically, it looks like:
[tex]\[
\text{Deviation} = \text{Sales} - \text{Average Sales}
\][/tex]
2. Given Data:
- Average sales for the period = \[tex]$1,460.83
- Sales for July = \$[/tex]1,750
- Sales for August = \[tex]$1,800
- Sales for September = \$[/tex]1,625
- Sales for October = \[tex]$1,395
- Sales for November = \$[/tex]1,215
- Sales for December = \[tex]$980
3. Calculate the Deviations:
For July:
\[
\text{Deviation for July} = 1750 - 1460.83 = 289.17
\]
For August:
\[
\text{Deviation for August} = 1800 - 1460.83 = 339.17
\]
For September:
\[
\text{Deviation for September} = 1625 - 1460.83 = 164.17
\]
For October:
Given deviation is -65.83, which is already known.
For November:
\[
\text{Deviation for November} = 1215 - 1460.83 = -245.83
\]
For December:
\[
\text{Deviation for December} = 980 - 1460.83 = -480.83
\]
### Final Values:
\[
\begin{array}{|l|l|l|r|}
\hline
\text{Month} & \text{Sales} & \text{Average} & \text{Deviation} \\
\hline
\text{July} & \$[/tex]1,750 & \[tex]$1,460.83 & 289.17 \\
\hline
\text{Aug.} & \$[/tex]1,800 & \[tex]$1,460.83 & 339.17 \\
\hline
\text{Sept.} & \$[/tex]1,625 & \[tex]$1,460.83 & 164.17 \\
\hline
\text{Oct.} & \$[/tex]1,395 & \[tex]$1,460.83 & -65.83 \\
\hline
\text{Nov.} & \$[/tex]1,215 & \[tex]$1,460.83 & -245.83 \\
\hline
\text{Dec.} & \$[/tex]980 & \[tex]$1,460.83 & -480.83 \\
\hline
\end{array}
\]
The table now gives us a complete view of the monthly deviations from the average sales figure of \$[/tex]1,460.83 for each of the months July through December.
