IDNLearn.com offers a comprehensive solution for all your question and answer needs. Receive prompt and accurate responses to your questions from our community of knowledgeable professionals ready to assist you at any time.

The equations of three lines are given below.

Line 1: [tex]y = 4x + 8[/tex]
Line 2: [tex]3x + 12y = -12[/tex]
Line 3: [tex]y = 4x - 5[/tex]

For each pair of lines, determine whether they are parallel, perpendicular, or neither.

1. Line 1 and Line 2:
A. Parallel
B. Perpendicular
C. Neither

2. Line 1 and Line 3:
A. Parallel
B. Perpendicular
C. Neither

3. Line 2 and Line 3:
A. Parallel
B. Perpendicular
C. Neither


Sagot :

To determine the relationship between given lines, we need to compare their slopes. Here are the steps to find the slopes and determine if they are parallel, perpendicular, or neither:

### Step 1: Find the slope of each line

Line 1: [tex]\( y = 4x + 8 \)[/tex]
- This equation is already in the slope-intercept form [tex]\( y = mx + b \)[/tex], where [tex]\( m \)[/tex] is the slope.
- The slope ([tex]\( m \)[/tex]) of Line 1 is [tex]\( 4 \)[/tex].

Line 2: [tex]\( 3x + 12y = -12 \)[/tex]
- To find the slope, we need to rewrite this equation in slope-intercept form [tex]\( y = mx + b \)[/tex].
- Solve for [tex]\( y \)[/tex]:
[tex]\[ 3x + 12y = -12 \][/tex]
[tex]\[ 12y = -3x - 12 \][/tex]
[tex]\[ y = -\frac{1}{4}x - 1 \][/tex]
- The slope ([tex]\( m \)[/tex]) of Line 2 is [tex]\( -\frac{1}{4} \)[/tex].

Line 3: [tex]\( y = 4x - 5 \)[/tex]
- This equation is already in slope-intercept form [tex]\( y = mx + b \)[/tex], where [tex]\( m \)[/tex] is the slope.
- The slope ([tex]\( m \)[/tex]) of Line 3 is [tex]\( 4 \)[/tex].

### Step 2: Compare the slopes

Line 1 and Line 2:
- Slope of Line 1: [tex]\( 4 \)[/tex]
- Slope of Line 2: [tex]\( -\frac{1}{4} \)[/tex]
- Two lines are perpendicular if the product of their slopes is [tex]\( -1 \)[/tex].
[tex]\[ 4 \times -\frac{1}{4} = -1 \][/tex]
- Thus, Line 1 and Line 2 are perpendicular.

Line 1 and Line 3:
- Slope of Line 1: [tex]\( 4 \)[/tex]
- Slope of Line 3: [tex]\( 4 \)[/tex]
- Two lines are parallel if they have the same slope.
- Since the slopes are equal, Line 1 and Line 3 are parallel.

Line 2 and Line 3:
- Slope of Line 2: [tex]\( -\frac{1}{4} \)[/tex]
- Slope of Line 3: [tex]\( 4 \)[/tex]
- Two lines are perpendicular if the product of their slopes is [tex]\( -1 \)[/tex].
[tex]\[ -\frac{1}{4} \times 4 = -1 \][/tex]
- Thus, Line 2 and Line 3 are perpendicular.

### Summary:
- Line 1 and Line 2: Perpendicular
- Line 1 and Line 3: Parallel
- Line 2 and Line 3: Perpendicular

So, the final relationships between the lines are:
[tex]\[ \begin{array}{l} \text{Line 1 and Line 2: Perpendicular} \\ \text{Line 1 and Line 3: Parallel} \\ \text{Line 2 and Line 3: Perpendicular} \end{array} \][/tex]