Find the best answers to your questions with the help of IDNLearn.com's knowledgeable users. Get accurate answers to your questions from our community of experts who are always ready to provide timely and relevant solutions.
Sagot :
Sure, let's write the standard equation of a circle with the given center [tex]\((-4, -1)\)[/tex] and radius 12 units.
The standard form of the equation of a circle with center [tex]\((h, k)\)[/tex] and radius [tex]\(r\)[/tex] is given by:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
In this case, the center [tex]\((h, k)\)[/tex] is [tex]\((-4, -1)\)[/tex], and the radius [tex]\(r\)[/tex] is 12 units. Substituting these values into the standard form equation, we get:
[tex]\[ (x - (-4))^2 + (y - (-1))^2 = 12^2 \][/tex]
Simplifying the equation:
[tex]\[ (x + 4)^2 + (y + 1)^2 = 144 \][/tex]
So, the standard equation of the circle with center [tex]\((-4, -1)\)[/tex] and radius 12 units is:
[tex]\[ (x + 4)^2 + (y + 1)^2 = 144 \][/tex]
The standard form of the equation of a circle with center [tex]\((h, k)\)[/tex] and radius [tex]\(r\)[/tex] is given by:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
In this case, the center [tex]\((h, k)\)[/tex] is [tex]\((-4, -1)\)[/tex], and the radius [tex]\(r\)[/tex] is 12 units. Substituting these values into the standard form equation, we get:
[tex]\[ (x - (-4))^2 + (y - (-1))^2 = 12^2 \][/tex]
Simplifying the equation:
[tex]\[ (x + 4)^2 + (y + 1)^2 = 144 \][/tex]
So, the standard equation of the circle with center [tex]\((-4, -1)\)[/tex] and radius 12 units is:
[tex]\[ (x + 4)^2 + (y + 1)^2 = 144 \][/tex]
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Discover the answers you need at IDNLearn.com. Thank you for visiting, and we hope to see you again for more solutions.