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APUNTES DE FÍSICA II: CINEMÁTICA Y DINÁMICA

3. Determina el trabajo realizado al desplazar un bloque 3 m sobre una superficie horizontal, si se desprecia la fricción y la fuerza aplicada tiene una magnitud de 25 N.

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Final answer:

The work done when moving a block 3 m with a force of 25 N on a horizontal surface is 75 Joules.


Explanation:

Work done is calculated by multiplying the force applied by the displacement and the cos of the angle between the force and displacement. In this case, work = force x displacement x cos(angle).

Given force of 25 N, displacement of 3 m, and angle of 0°, work = 25 N x 3 m x cos(0°) = 75 Joules.

Therefore, the work done when moving a block 3 m with a force of 25 N on a horizontal surface is 75 Joules.


Learn more about work calculation in physics here:

https://brainly.com/question/33726554


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