Find answers to your questions and expand your knowledge with IDNLearn.com. Our community provides accurate and timely answers to help you understand and solve any issue.
Sagot :
To determine the multiplicative rate of change of the given exponential function, we need to examine how the value of [tex]\(y\)[/tex] changes as [tex]\(x\)[/tex] increases. Let’s go through the steps systematically:
1. Identify the given data points:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 6 \\ \hline 2 & 4 \\ \hline 3 & \frac{8}{3} \\ \hline 4 & \frac{16}{9} \\ \hline \end{array} \][/tex]
2. Calculate the multiplicative rate of change between consecutive [tex]\(y\)[/tex]-values:
The rate of change between two consecutive points [tex]\((x_i, y_i)\)[/tex] and [tex]\((x_{i+1}, y_{i+1})\)[/tex] in an exponential function should be consistent. Therefore, we compute:
[tex]\[ \text{Rate of change from } x = 1 \text{ to } x = 2: \frac{y_2}{y_1} = \frac{4}{6} = \frac{2}{3} \][/tex]
[tex]\[ \text{Rate of change from } x = 2 \text{ to } x = 3: \frac{y_3}{y_2} = \frac{\frac{8}{3}}{4} = \frac{8}{3} \cdot \frac{1}{4} = \frac{8}{12} = \frac{2}{3} \][/tex]
[tex]\[ \text{Rate of change from } x = 3 \text{ to } x = 4: \frac{y_4}{y_3} = \frac{\frac{16}{9}}{\frac{8}{3}} = \frac{16}{9} \cdot \frac{3}{8} = \frac{48}{72} = \frac{2}{3} \][/tex]
3. Evaluate the consistency of the rate of change:
All calculated rates of change are [tex]\(\frac{2}{3}\)[/tex], indicating a consistent multiplicative rate of change, as expected for an exponential function.
4. Conclusion:
The multiplicative rate of change for the given exponential function is:
[tex]\[ \boxed{\frac{2}{3}} \][/tex]
1. Identify the given data points:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 6 \\ \hline 2 & 4 \\ \hline 3 & \frac{8}{3} \\ \hline 4 & \frac{16}{9} \\ \hline \end{array} \][/tex]
2. Calculate the multiplicative rate of change between consecutive [tex]\(y\)[/tex]-values:
The rate of change between two consecutive points [tex]\((x_i, y_i)\)[/tex] and [tex]\((x_{i+1}, y_{i+1})\)[/tex] in an exponential function should be consistent. Therefore, we compute:
[tex]\[ \text{Rate of change from } x = 1 \text{ to } x = 2: \frac{y_2}{y_1} = \frac{4}{6} = \frac{2}{3} \][/tex]
[tex]\[ \text{Rate of change from } x = 2 \text{ to } x = 3: \frac{y_3}{y_2} = \frac{\frac{8}{3}}{4} = \frac{8}{3} \cdot \frac{1}{4} = \frac{8}{12} = \frac{2}{3} \][/tex]
[tex]\[ \text{Rate of change from } x = 3 \text{ to } x = 4: \frac{y_4}{y_3} = \frac{\frac{16}{9}}{\frac{8}{3}} = \frac{16}{9} \cdot \frac{3}{8} = \frac{48}{72} = \frac{2}{3} \][/tex]
3. Evaluate the consistency of the rate of change:
All calculated rates of change are [tex]\(\frac{2}{3}\)[/tex], indicating a consistent multiplicative rate of change, as expected for an exponential function.
4. Conclusion:
The multiplicative rate of change for the given exponential function is:
[tex]\[ \boxed{\frac{2}{3}} \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.