Find answers to your questions and expand your knowledge with IDNLearn.com. Our community provides accurate and timely answers to help you understand and solve any issue.

The table represents an exponential function.

[tex]\[
\begin{tabular}{|c|c|}
\hline
$x$ & $y$ \\
\hline
1 & 6 \\
\hline
2 & 4 \\
\hline
3 & $\frac{8}{3}$ \\
\hline
4 & $\frac{16}{9}$ \\
\hline
\end{tabular}
\][/tex]

What is the multiplicative rate of change of the function?

A. [tex]$\frac{1}{3}$[/tex]

B. [tex]$\frac{2}{3}$[/tex]

C. 2

D. 9


Sagot :

To determine the multiplicative rate of change of the given exponential function, we need to examine how the value of [tex]\(y\)[/tex] changes as [tex]\(x\)[/tex] increases. Let’s go through the steps systematically:

1. Identify the given data points:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 6 \\ \hline 2 & 4 \\ \hline 3 & \frac{8}{3} \\ \hline 4 & \frac{16}{9} \\ \hline \end{array} \][/tex]

2. Calculate the multiplicative rate of change between consecutive [tex]\(y\)[/tex]-values:
The rate of change between two consecutive points [tex]\((x_i, y_i)\)[/tex] and [tex]\((x_{i+1}, y_{i+1})\)[/tex] in an exponential function should be consistent. Therefore, we compute:
[tex]\[ \text{Rate of change from } x = 1 \text{ to } x = 2: \frac{y_2}{y_1} = \frac{4}{6} = \frac{2}{3} \][/tex]

[tex]\[ \text{Rate of change from } x = 2 \text{ to } x = 3: \frac{y_3}{y_2} = \frac{\frac{8}{3}}{4} = \frac{8}{3} \cdot \frac{1}{4} = \frac{8}{12} = \frac{2}{3} \][/tex]

[tex]\[ \text{Rate of change from } x = 3 \text{ to } x = 4: \frac{y_4}{y_3} = \frac{\frac{16}{9}}{\frac{8}{3}} = \frac{16}{9} \cdot \frac{3}{8} = \frac{48}{72} = \frac{2}{3} \][/tex]

3. Evaluate the consistency of the rate of change:
All calculated rates of change are [tex]\(\frac{2}{3}\)[/tex], indicating a consistent multiplicative rate of change, as expected for an exponential function.

4. Conclusion:
The multiplicative rate of change for the given exponential function is:
[tex]\[ \boxed{\frac{2}{3}} \][/tex]