Get comprehensive solutions to your problems with IDNLearn.com. Our platform is designed to provide reliable and thorough answers to all your questions, no matter the topic.

Use the following Intravenous Heparin protocol to answer the following questions:

\begin{tabular}{|c|c|c|c|}
\hline
aPTT (sec) & \begin{tabular}{c}
Bolus \\
Dose \\
(units/kg)
\end{tabular} & \begin{tabular}{c}
Stop \\
Infusion \\
(min)
\end{tabular} & Rate Change (units/kg/h) \\
\hline
Initial dose & 80 & & 18 (initial rate) \\
\hline
[tex]$\ \textless \ $[/tex]34 & 80 & & Increase by 4 \\
\hline
[tex]$35-59$[/tex] & 40 & & Increase by 2 \\
\hline
[tex]$60-90$[/tex] & No & & No change \\
\hline
[tex]$91-110$[/tex] & No & & Decrease by 1 \\
\hline
[tex]$111-212$[/tex] & No & & Decrease by 2 \\
\hline
[tex]$\ \textgreater \ $[/tex]212 & No & 60 & Decrease by 3 \\
\hline
\end{tabular}

The IV is infusing at [tex]$28 \text{ mL/h}$[/tex]. Calculate the rate change if the patient's aPTT was 110. What is the new rate?

A. [tex]$25 \text{ mL/h}$[/tex]

B. [tex]$29 \text{ mL/h}$[/tex]

C. [tex]$27 \text{ mL/h}$[/tex]

D. [tex]$30 \text{ mL/h}$[/tex]


Sagot :

To determine the rate change and calculate the new rate based on the given protocol and the patient's aPTT value, follow these steps:

1. Identify the current infusion rate:
- The initial infusion rate is given as [tex]\(28 \, \text{mL/h}\)[/tex].

2. Determine the patient’s aPTT value:
- The patient's aPTT value given in the problem is [tex]\(110\)[/tex].

3. Refer to the aPTT protocol table:
- According to the protocol:
- If the aPTT is [tex]\(91-110\)[/tex] seconds, the rate should decrease by [tex]\(1 \, \text{unit/kgh}\)[/tex].

4. Calculate the rate change:
- The rate change corresponding to an aPTT of [tex]\(110\)[/tex] is a decrease by [tex]\(1 \, \text{unit/kgh}\)[/tex].

5. Apply the rate change to the initial infusion rate:
- Initial rate: [tex]\(28 \, \text{mL/h}\)[/tex]
- Decrease by: [tex]\(1 \, \text{mL/h}\)[/tex]

6. Calculate the new rate:
- New rate = Initial rate - Rate change
- New rate = [tex]\(28 \, \text{mL/h} - 1 \, \text{mL/h} = 27 \, \text{mL/h}\)[/tex]

Thus, the new infusion rate will be [tex]\(27 \, \text{mL/h}\)[/tex].

Answer: [tex]\(\mathbf{27 \, \text{mL/h}}\)[/tex]