To solve this question, we need to understand the relationship between power, work done, and time. The formula connecting these quantities is:
[tex]\[ \text{Power} (P) = \frac{\text{Work done} (W)}{\text{Time} (t)} \][/tex]
Given:
- Power ([tex]\(P\)[/tex]) = 900 W
- Time ([tex]\(t\)[/tex]) = 30 s
We are asked to find the work done ([tex]\(W\)[/tex]). Rearanging the formula to solve for work done, we have:
[tex]\[ W = P \times t \][/tex]
Now we can substitute the given values into the equation:
[tex]\[ W = 900 \, \text{W} \times 30 \, \text{s} \][/tex]
[tex]\[ W = 27000 \, \text{Joules} \][/tex]
Therefore, the work done by the motor is [tex]\(27,000 \, \text{J}\)[/tex].
The correct answer is:
[tex]\[ 27,000 \, \text{J} \][/tex]
