Get the information you need with the help of IDNLearn.com's expert community. Whether it's a simple query or a complex problem, our experts have the answers you need.
Sagot :
To solve this problem, let’s break it down step-by-step:
1. Understanding the problem:
- We start with 3.45 moles of [tex]\( \text{KMnO}_4 \)[/tex].
- For each 2 moles of [tex]\( \text{KMnO}_4 \)[/tex], 8 moles of [tex]\( \text{H}_2\text{O} \)[/tex] are produced.
2. Setting up the ratio:
- The ratio of [tex]\( \text{H}_2\text{O} \)[/tex] to [tex]\( \text{KMnO}_4 \)[/tex] is given by [tex]\( \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} \)[/tex].
- Simplifying this ratio, [tex]\( \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} = 4 \, \text{mol} \, \text{H}_2\text{O} / 1 \, \text{mol} \, \text{KMnO}_4 \)[/tex].
3. Calculating the amount of [tex]\( \text{H}_2\text{O} \)[/tex] produced:
- We need to multiply the given moles of [tex]\( \text{KMnO}_4 \)[/tex] by the simplified ratio.
- Calculation: [tex]\( 3.45 \, \text{mol} \, \text{KMnO}_4 \times 4 \, \text{mol} \, \text{H}_2\text{O} / 1 \, \text{mol} \, \text{KMnO}_4 \)[/tex].
4. Performing the multiplication:
- This yields [tex]\( 3.45 \times 4 = 13.8 \, \text{mol} \, \text{H}_2\text{O} \)[/tex].
In summary, your initial setup was correct:
- You correctly used the ratio [tex]\( \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} \)[/tex].
- Simplified it to [tex]\( 4 \, \text{mol} \, \text{H}_2\text{O} \)[/tex] per [tex]\( 1 \, \text{mol} \, \text{KMnO}_4 \)[/tex].
- Correctly multiplied [tex]\( 3.45 \, \text{mol} \, \text{KMnO}_4 \)[/tex] by [tex]\( 4 \)[/tex] to get [tex]\( 13.8 \, \text{mol} \, \text{H}_2\text{O} \)[/tex].
Therefore, you set up the equation correctly and executed the calculation correctly, obtaining the correct answer.
1. Understanding the problem:
- We start with 3.45 moles of [tex]\( \text{KMnO}_4 \)[/tex].
- For each 2 moles of [tex]\( \text{KMnO}_4 \)[/tex], 8 moles of [tex]\( \text{H}_2\text{O} \)[/tex] are produced.
2. Setting up the ratio:
- The ratio of [tex]\( \text{H}_2\text{O} \)[/tex] to [tex]\( \text{KMnO}_4 \)[/tex] is given by [tex]\( \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} \)[/tex].
- Simplifying this ratio, [tex]\( \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} = 4 \, \text{mol} \, \text{H}_2\text{O} / 1 \, \text{mol} \, \text{KMnO}_4 \)[/tex].
3. Calculating the amount of [tex]\( \text{H}_2\text{O} \)[/tex] produced:
- We need to multiply the given moles of [tex]\( \text{KMnO}_4 \)[/tex] by the simplified ratio.
- Calculation: [tex]\( 3.45 \, \text{mol} \, \text{KMnO}_4 \times 4 \, \text{mol} \, \text{H}_2\text{O} / 1 \, \text{mol} \, \text{KMnO}_4 \)[/tex].
4. Performing the multiplication:
- This yields [tex]\( 3.45 \times 4 = 13.8 \, \text{mol} \, \text{H}_2\text{O} \)[/tex].
In summary, your initial setup was correct:
- You correctly used the ratio [tex]\( \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} \)[/tex].
- Simplified it to [tex]\( 4 \, \text{mol} \, \text{H}_2\text{O} \)[/tex] per [tex]\( 1 \, \text{mol} \, \text{KMnO}_4 \)[/tex].
- Correctly multiplied [tex]\( 3.45 \, \text{mol} \, \text{KMnO}_4 \)[/tex] by [tex]\( 4 \)[/tex] to get [tex]\( 13.8 \, \text{mol} \, \text{H}_2\text{O} \)[/tex].
Therefore, you set up the equation correctly and executed the calculation correctly, obtaining the correct answer.
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Trust IDNLearn.com for all your queries. We appreciate your visit and hope to assist you again soon.