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3) In the following numbers, the irrational number is:

A. [tex]\sqrt{16} - \sqrt{9}[/tex]
B. [tex]\frac{3}{4}[/tex]
C. 0.3333
D. [tex]2 + \sqrt{3}[/tex]


Sagot :

To find out the irrational number among the given options, let's analyze each option step by step.

Option A: [tex]\(\sqrt{16} - \sqrt{9}\)[/tex]

- [tex]\(\sqrt{16} = 4\)[/tex]
- [tex]\(\sqrt{9} = 3\)[/tex]
- Therefore, [tex]\(\sqrt{16} - \sqrt{9} = 4 - 3 = 1\)[/tex]

Since 1 is a rational number, Option A is not an irrational number.

Option B: [tex]\(\frac{3}{4}\)[/tex]

- [tex]\(\frac{3}{4}\)[/tex] is already a fraction of two integers (3 and 4), which means it's a rational number.

So, Option B is not an irrational number.

Option C: 0.3333

- 0.3333 is a decimal representation that can be approximated by a fraction, specifically [tex]\(\frac{3333}{10000}\)[/tex].

Since 0.3333 can be represented as a fraction, it is a rational number.

Option D: [tex]\(2 + \sqrt{3}\)[/tex]

- [tex]\(2\)[/tex] is a rational number.
- [tex]\(\sqrt{3}\)[/tex] is an irrational number because it cannot be expressed as a fraction of two integers.
- The sum of a rational number and an irrational number is always irrational.

Thus, [tex]\(2 + \sqrt{3}\)[/tex] is an irrational number.

Given this analysis, the irrational number among the options is:

D) [tex]\(2 + \sqrt{3}\)[/tex]

Hence, the correct answer is [tex]\(4\)[/tex].