Join the growing community of curious minds on IDNLearn.com and get the answers you need. Get accurate and comprehensive answers to your questions from our community of knowledgeable professionals.
Sagot :
Answer: 4.59
Step-by-step explanation:When capacitors are connected in series, the total capacitance (C_total) can be calculated using the formula:
1/C_total = 1/C1 + 1/C2
Given that C1 = 6.0 μF and C2 = 8.0 μF, we can find the total capacitance:
1/C_total = 1/6 + 1/8
1/C_total = (4/24) + (3/24)
1/C_total = (7/24)
C_total = 24/7 ≈ 3.429 μF
In a series circuit, the voltage across each capacitor depends on the ratio of their capacitances to the total capacitance, multiplied by the total voltage. So, the voltage across the 6.0 μF capacitor (V_6) can be found as follows:
V_6 = (C_total / C1) * V_total
V_6 = (3.429 / 6.0) * 8.0
V_6 ≈ 4.59 V
Therefore, the voltage across the 6.0 μF capacitor in this series circuit is approximately 4.59 V.
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.
