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\begin{tabular}{|c|c|c|}
\hline
Número de baños & Frecuencia absoluta & Frecuencia relativa (s) \\
\hline
1 & 2 & [tex]$2 / 25 = 0.08$[/tex] \\
\hline
2 & 3 & \\
\hline
[tex]$\frac{21}{2}$[/tex] & 1 & \\
\hline
3 & 10 & \\
\hline
[tex]$\frac{31}{2}$[/tex] & 1 & \\
\hline
4 & 3 & \\
\hline
[tex]$\frac{41}{2}$[/tex] & 1 & \\
\hline
5 & 3 & \\
\hline
6 & & \\
\hline
TOTAL & & \\
\hline
\end{tabular}


Sagot :

Certainly! Let's fill in the missing relative frequencies and the total values step-by-step!

Given the data, we have:

- Absolute frequencies for the various values.
- The total count is 25.

We need to fill in the relative frequencies and compute the totals.

Here's the table with the calculated relative frequencies:

\begin{array}{|c|c|c|}
\hline \text{Numero de banios} & \text{Frecuencia absoluta} & \text{Frecuencia relativa} \\
\hline 1 & 2 & \frac{2}{25}=0.08 \\
\hline 2 & 3 & \frac{3}{25}=0.12 \\
\hline 21/2 & 1 & \frac{1}{25}=0.04 \\
\hline 3 & 10 & \frac{10}{25}=0.40 \\
\hline 31/2 & 1 & \frac{1}{25}=0.04 \\
\hline 4 & 3 & \frac{3}{25}=0.12 \\
\hline 41/2 & 1 & \frac{1}{25}=0.04 \\
\hline 5 & 3 & \frac{3}{25}=0.12 \\
\hline 6 & 0 & \frac{0}{25}=0.00 \\
\hline \text{TOTAL} & 25 & 1.00 \\
\hline
\end{array}

Here's the detailed step-by-step process we followed:

1. Calculate relative frequencies:
- For 1 bathroom: [tex]\(\frac{2}{25} = 0.08\)[/tex]
- For 2 bathrooms: [tex]\(\frac{3}{25} = 0.12\)[/tex]
- For [tex]\(\frac{21}{2}\)[/tex] bathrooms: [tex]\(\frac{1}{25} = 0.04\)[/tex]
- For 3 bathrooms: [tex]\(\frac{10}{25} = 0.40\)[/tex]
- For [tex]\(\frac{31}{2}\)[/tex] bathrooms: [tex]\(\frac{1}{25} = 0.04\)[/tex]
- For 4 bathrooms: [tex]\(\frac{3}{25} = 0.12\)[/tex]
- For [tex]\(\frac{41}{2}\)[/tex] bathrooms: [tex]\(\frac{1}{25} = 0.04\)[/tex]
- For 5 bathrooms: [tex]\(\frac{3}{25} = 0.12\)[/tex]
- For 6 bathrooms: [tex]\(\frac{0}{25} = 0.00\)[/tex]

2. Calculate the total absolute frequency:
- The sum of all absolute frequencies is given as 25.

3. Ensure the total of the relative frequencies sums to 1.00:
- [tex]\(0.08 + 0.12 + 0.04 + 0.40 + 0.04 + 0.12 + 0.04 + 0.12 + 0.00 = 1.00\)[/tex]

The final table represents the frequency distribution accurately, with both absolute and relative frequencies correctly calculated and the totals summing to the expected values.
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