Connect with a global community of experts on IDNLearn.com. Our community is here to provide the comprehensive and accurate answers you need to make informed decisions.
Sagot :
To determine which equation could represent a parabola with a minimum at the point [tex]\((-3,9)\)[/tex], we need to observe the following characteristics of the function:
1. Vertex Form of a Parabola: The general vertex form of a quadratic function is given by [tex]\( g(x) = a(x-h)^2 + k \)[/tex] where [tex]\((h, k)\)[/tex] is the vertex of the parabola.
2. Minimum Point: The value of [tex]\(a\)[/tex] in the equation will determine if the parabola opens upwards (minimum point) or downwards (maximum point). If [tex]\(a > 0\)[/tex], the parabola opens upwards, making [tex]\((h, k)\)[/tex] a minimum point. If [tex]\(a < 0\)[/tex], the parabola opens downwards, making [tex]\((h, k)\)[/tex] a maximum point.
3. Given vertex: For the point [tex]\((-3, 9)\)[/tex], the vertex form should be [tex]\( g(x) = a(x+3)^2 + 9 \)[/tex], indicating that the vertex [tex]\((h, k)\)[/tex] corresponds to [tex]\(h = -3\)[/tex] and [tex]\(k = 9\)[/tex].
Now, let's analyze the given options:
A. [tex]\( g(x) = 3(x-3)^2 + 9 \)[/tex]
- Here, the vertex form suggests [tex]\(h = 3\)[/tex] and [tex]\(k = 9\)[/tex], which gives a vertex at point [tex]\((3, 9)\)[/tex]. This does not match our given vertex of [tex]\((-3, 9)\)[/tex].
B. [tex]\( g(x) = -(x+3)^2 + 9 \)[/tex]
- Here, the vertex form suggests [tex]\(h = -3\)[/tex] and [tex]\(k = 9\)[/tex], which gives a vertex at point [tex]\((-3, 9)\)[/tex]. However, the coefficient of the quadratic term is negative ([tex]\( -1 \)[/tex]), indicating that the parabola opens downwards and thus the point [tex]\((-3, 9)\)[/tex] is a maximum point. This contradicts the requirement of having a minimum.
C. [tex]\( g(x) = -\frac{1}{2}(x-3)^2 + 9 \)[/tex]
- Here, the vertex form suggests [tex]\(h = 3\)[/tex] and [tex]\(k = 9\)[/tex], which gives a vertex at point [tex]\((3, 9)\)[/tex]. This does not match our given vertex of [tex]\((-3, 9)\)[/tex].
D. [tex]\( g(x) = 2(x+3)^2 + 9 \)[/tex]
- Here, the vertex form suggests [tex]\(h = -3\)[/tex] and [tex]\(k = 9\)[/tex], which gives a vertex at point [tex]\((-3, 9)\)[/tex]. The coefficient of the quadratic term is positive ([tex]\( 2 \)[/tex]), indicating that the parabola opens upwards and hence the point [tex]\((-3, 9)\)[/tex] is a minimum point.
Since [tex]\( g(x) = 2(x+3)^2 + 9 \)[/tex] matches all the given characteristics correctly, the correct answer is:
D. [tex]\( g(x)=2(x+3)^2+9 \)[/tex]
1. Vertex Form of a Parabola: The general vertex form of a quadratic function is given by [tex]\( g(x) = a(x-h)^2 + k \)[/tex] where [tex]\((h, k)\)[/tex] is the vertex of the parabola.
2. Minimum Point: The value of [tex]\(a\)[/tex] in the equation will determine if the parabola opens upwards (minimum point) or downwards (maximum point). If [tex]\(a > 0\)[/tex], the parabola opens upwards, making [tex]\((h, k)\)[/tex] a minimum point. If [tex]\(a < 0\)[/tex], the parabola opens downwards, making [tex]\((h, k)\)[/tex] a maximum point.
3. Given vertex: For the point [tex]\((-3, 9)\)[/tex], the vertex form should be [tex]\( g(x) = a(x+3)^2 + 9 \)[/tex], indicating that the vertex [tex]\((h, k)\)[/tex] corresponds to [tex]\(h = -3\)[/tex] and [tex]\(k = 9\)[/tex].
Now, let's analyze the given options:
A. [tex]\( g(x) = 3(x-3)^2 + 9 \)[/tex]
- Here, the vertex form suggests [tex]\(h = 3\)[/tex] and [tex]\(k = 9\)[/tex], which gives a vertex at point [tex]\((3, 9)\)[/tex]. This does not match our given vertex of [tex]\((-3, 9)\)[/tex].
B. [tex]\( g(x) = -(x+3)^2 + 9 \)[/tex]
- Here, the vertex form suggests [tex]\(h = -3\)[/tex] and [tex]\(k = 9\)[/tex], which gives a vertex at point [tex]\((-3, 9)\)[/tex]. However, the coefficient of the quadratic term is negative ([tex]\( -1 \)[/tex]), indicating that the parabola opens downwards and thus the point [tex]\((-3, 9)\)[/tex] is a maximum point. This contradicts the requirement of having a minimum.
C. [tex]\( g(x) = -\frac{1}{2}(x-3)^2 + 9 \)[/tex]
- Here, the vertex form suggests [tex]\(h = 3\)[/tex] and [tex]\(k = 9\)[/tex], which gives a vertex at point [tex]\((3, 9)\)[/tex]. This does not match our given vertex of [tex]\((-3, 9)\)[/tex].
D. [tex]\( g(x) = 2(x+3)^2 + 9 \)[/tex]
- Here, the vertex form suggests [tex]\(h = -3\)[/tex] and [tex]\(k = 9\)[/tex], which gives a vertex at point [tex]\((-3, 9)\)[/tex]. The coefficient of the quadratic term is positive ([tex]\( 2 \)[/tex]), indicating that the parabola opens upwards and hence the point [tex]\((-3, 9)\)[/tex] is a minimum point.
Since [tex]\( g(x) = 2(x+3)^2 + 9 \)[/tex] matches all the given characteristics correctly, the correct answer is:
D. [tex]\( g(x)=2(x+3)^2+9 \)[/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.