Find solutions to your problems with the help of IDNLearn.com's knowledgeable users. Find in-depth and accurate answers to all your questions from our knowledgeable and dedicated community members.
Sagot :
To determine whether the events [tex]\( X \)[/tex] and [tex]\( Y \)[/tex] are mutually exclusive, let’s review some key concepts and follow the logical steps.
### Key Concepts:
1. Mutually Exclusive Events: Two events are mutually exclusive if they cannot occur at the same time. When two events are mutually exclusive, the probability of their intersection is zero; that is, [tex]\( P(X \cap Y) = 0 \)[/tex].
2. Addition Rule for Mutually Exclusive Events: If events [tex]\( X \)[/tex] and [tex]\( Y \)[/tex] are mutually exclusive, then the probability of their union is the sum of their individual probabilities:
[tex]\[ P(X \cup Y) = P(X) + P(Y) \][/tex]
### Given Information:
- [tex]\( P(Y) = 0.25 \)[/tex]
- [tex]\( P(X) = 0.2 \)[/tex]
For [tex]\( X \)[/tex] and [tex]\( Y \)[/tex] to be mutually exclusive, the following condition needs to be satisfied:
[tex]\[ P(X \cap Y) = 0 \][/tex]
Given that they are mutually exclusive, we use the addition rule:
[tex]\[ P(X \cup Y) = P(X) + P(Y) \][/tex]
Substitute the known probabilities:
[tex]\[ P(X \cup Y) = 0.2 + 0.25 = 0.45 \][/tex]
Since the sum of [tex]\( P(X) \)[/tex] and [tex]\( P(Y) \)[/tex] is [tex]\( 0.45 \)[/tex], which is less than or equal to [tex]\( 1 \)[/tex], the condition for the probabilities of mutually exclusive events is satisfied.
### Conclusion:
Given that the sum of [tex]\( P(X) \)[/tex] and [tex]\( P(Y) \)[/tex] is less than or equal to 1, the events [tex]\( X \)[/tex] and [tex]\( Y \)[/tex] are indeed mutually exclusive. Therefore, the correct answer is:
True
### Key Concepts:
1. Mutually Exclusive Events: Two events are mutually exclusive if they cannot occur at the same time. When two events are mutually exclusive, the probability of their intersection is zero; that is, [tex]\( P(X \cap Y) = 0 \)[/tex].
2. Addition Rule for Mutually Exclusive Events: If events [tex]\( X \)[/tex] and [tex]\( Y \)[/tex] are mutually exclusive, then the probability of their union is the sum of their individual probabilities:
[tex]\[ P(X \cup Y) = P(X) + P(Y) \][/tex]
### Given Information:
- [tex]\( P(Y) = 0.25 \)[/tex]
- [tex]\( P(X) = 0.2 \)[/tex]
For [tex]\( X \)[/tex] and [tex]\( Y \)[/tex] to be mutually exclusive, the following condition needs to be satisfied:
[tex]\[ P(X \cap Y) = 0 \][/tex]
Given that they are mutually exclusive, we use the addition rule:
[tex]\[ P(X \cup Y) = P(X) + P(Y) \][/tex]
Substitute the known probabilities:
[tex]\[ P(X \cup Y) = 0.2 + 0.25 = 0.45 \][/tex]
Since the sum of [tex]\( P(X) \)[/tex] and [tex]\( P(Y) \)[/tex] is [tex]\( 0.45 \)[/tex], which is less than or equal to [tex]\( 1 \)[/tex], the condition for the probabilities of mutually exclusive events is satisfied.
### Conclusion:
Given that the sum of [tex]\( P(X) \)[/tex] and [tex]\( P(Y) \)[/tex] is less than or equal to 1, the events [tex]\( X \)[/tex] and [tex]\( Y \)[/tex] are indeed mutually exclusive. Therefore, the correct answer is:
True
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.