Get detailed and accurate answers to your questions on IDNLearn.com. Discover prompt and accurate answers from our community of experienced professionals.
Sagot :
To solve the equation [tex]\( 4^{2x-3} = 7^x + 2^{x+2} \)[/tex], let's break it down step by step:
1. Rewrite the bases with exponents:
[tex]\[ 4^{2x-3} = (2^2)^{2x-3} = 2^{4x-6} \][/tex]
Similarly, for the right-hand side:
[tex]\[ 2^{x+2} = 2^x \cdot 2^2 = 4 \cdot 2^x \][/tex]
So the equation becomes:
[tex]\[ 2^{4x-6} = 7^x + 4 \cdot 2^x \][/tex]
2. Analyze possible solutions:
This is a transcendental equation, which means it typically does not have a straightforward analytical solution like algebraic equations. Instead, we often need numerical methods to find approximate solutions or argue about possible solutions by substituting feasible numbers.
3. Substitute potential solutions:
Let's test a few values of [tex]\( x \)[/tex] to see if we can find a solution:
- Test [tex]\( x = 0 \)[/tex]:
[tex]\[ 2^{4(0)-6} = 2^{-6} = \frac{1}{2^6} = \frac{1}{64} \][/tex]
[tex]\[ 7^0 + 4 \cdot 2^0 = 1 + 4 = 5 \][/tex]
Clearly, [tex]\( \frac{1}{64} \ne 5 \)[/tex].
- Test [tex]\( x = 1 \)[/tex]:
[tex]\[ 2^{4(1)-6} = 2^{-2} = \frac{1}{2^2} = \frac{1}{4} \][/tex]
[tex]\[ 7^1 + 4 \cdot 2^1 = 7 + 8 = 15 \][/tex]
Again, [tex]\( \frac{1}{4} \ne 15 \)[/tex].
- Test [tex]\( x = 2 \)[/tex]:
[tex]\[ 2^{4(2)-6} = 2^2 = 4 \][/tex]
[tex]\[ 7^2 + 4 \cdot 2^2 = 49 + 16 = 65 \][/tex]
[tex]\( 4 \ne 65 \)[/tex].
- Test [tex]\( x = 3 \)[/tex]:
[tex]\[ 2^{4(3)-6} = 2^{12-6} = 2^6 = 64 \][/tex]
[tex]\[ 7^3 + 4 \cdot 2^3 = 343 + 4 \cdot 8 = 343 + 32 = 375 \][/tex]
[tex]\( 64 \ne 375 \)[/tex].
Given that simple values like 0, 1, 2, and 3 do not solve the equation, and the nature of the equation, we should generally expect that a transcendental equation like this will be best approached either graphically or with numerical methods (e.g., using a computer algebra system, iterative methods, or other numerical techniques).
Let's conclude by offering the observation that solving [tex]\( 2^{4x-6} = 7^x + 4 \cdot 2^x \)[/tex] exactly requires numerical methods due to its complexity. Graphically plotting [tex]\( y = 2^{4x-6} \)[/tex] and [tex]\( y = 7^x + 4 \cdot 2^x \)[/tex] would provide the intersection points, which provide the solutions for [tex]\( x \)[/tex]. From the attempts above, no simple analytical solution exists.
1. Rewrite the bases with exponents:
[tex]\[ 4^{2x-3} = (2^2)^{2x-3} = 2^{4x-6} \][/tex]
Similarly, for the right-hand side:
[tex]\[ 2^{x+2} = 2^x \cdot 2^2 = 4 \cdot 2^x \][/tex]
So the equation becomes:
[tex]\[ 2^{4x-6} = 7^x + 4 \cdot 2^x \][/tex]
2. Analyze possible solutions:
This is a transcendental equation, which means it typically does not have a straightforward analytical solution like algebraic equations. Instead, we often need numerical methods to find approximate solutions or argue about possible solutions by substituting feasible numbers.
3. Substitute potential solutions:
Let's test a few values of [tex]\( x \)[/tex] to see if we can find a solution:
- Test [tex]\( x = 0 \)[/tex]:
[tex]\[ 2^{4(0)-6} = 2^{-6} = \frac{1}{2^6} = \frac{1}{64} \][/tex]
[tex]\[ 7^0 + 4 \cdot 2^0 = 1 + 4 = 5 \][/tex]
Clearly, [tex]\( \frac{1}{64} \ne 5 \)[/tex].
- Test [tex]\( x = 1 \)[/tex]:
[tex]\[ 2^{4(1)-6} = 2^{-2} = \frac{1}{2^2} = \frac{1}{4} \][/tex]
[tex]\[ 7^1 + 4 \cdot 2^1 = 7 + 8 = 15 \][/tex]
Again, [tex]\( \frac{1}{4} \ne 15 \)[/tex].
- Test [tex]\( x = 2 \)[/tex]:
[tex]\[ 2^{4(2)-6} = 2^2 = 4 \][/tex]
[tex]\[ 7^2 + 4 \cdot 2^2 = 49 + 16 = 65 \][/tex]
[tex]\( 4 \ne 65 \)[/tex].
- Test [tex]\( x = 3 \)[/tex]:
[tex]\[ 2^{4(3)-6} = 2^{12-6} = 2^6 = 64 \][/tex]
[tex]\[ 7^3 + 4 \cdot 2^3 = 343 + 4 \cdot 8 = 343 + 32 = 375 \][/tex]
[tex]\( 64 \ne 375 \)[/tex].
Given that simple values like 0, 1, 2, and 3 do not solve the equation, and the nature of the equation, we should generally expect that a transcendental equation like this will be best approached either graphically or with numerical methods (e.g., using a computer algebra system, iterative methods, or other numerical techniques).
Let's conclude by offering the observation that solving [tex]\( 2^{4x-6} = 7^x + 4 \cdot 2^x \)[/tex] exactly requires numerical methods due to its complexity. Graphically plotting [tex]\( y = 2^{4x-6} \)[/tex] and [tex]\( y = 7^x + 4 \cdot 2^x \)[/tex] would provide the intersection points, which provide the solutions for [tex]\( x \)[/tex]. From the attempts above, no simple analytical solution exists.
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.