Experience the power of community-driven knowledge on IDNLearn.com. Ask your questions and receive comprehensive, trustworthy responses from our dedicated team of experts.
Sagot :
To simplify the expression [tex]\(\sqrt{24} - 2 \sqrt{12} + 7 \sqrt{6}\)[/tex], let's break down the terms step-by-step.
1. First, simplify [tex]\(\sqrt{24}\)[/tex]:
[tex]\[ \sqrt{24} = \sqrt{4 \times 6} = \sqrt{4} \times \sqrt{6} = 2\sqrt{6} \][/tex]
2. Next, simplify [tex]\(2 \sqrt{12}\)[/tex]:
[tex]\[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3} \][/tex]
Thus,
[tex]\[ 2 \sqrt{12} = 2 \times 2 \sqrt{3} = 4 \sqrt{3} \][/tex]
3. The term [tex]\(7 \sqrt{6}\)[/tex] remains as is since it is already in its simplest form.
Now, we combine the simplified terms:
[tex]\[ 2 \sqrt{6} - 4 \sqrt{3} + 7 \sqrt{6} \][/tex]
Combine the like terms involving [tex]\(\sqrt{6}\)[/tex]:
[tex]\[ (2 \sqrt{6} + 7 \sqrt{6}) - 4 \sqrt{3} = 9 \sqrt{6} - 4 \sqrt{3} \][/tex]
So the expression in simplified form is:
[tex]\[ 7 \sqrt{6} - 2 \sqrt{3} \][/tex]
Among the given choices, the correct simplified form of the expression is:
[tex]\[ \boxed{7 \sqrt{6} - 2 \sqrt{3}} \][/tex]
1. First, simplify [tex]\(\sqrt{24}\)[/tex]:
[tex]\[ \sqrt{24} = \sqrt{4 \times 6} = \sqrt{4} \times \sqrt{6} = 2\sqrt{6} \][/tex]
2. Next, simplify [tex]\(2 \sqrt{12}\)[/tex]:
[tex]\[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3} \][/tex]
Thus,
[tex]\[ 2 \sqrt{12} = 2 \times 2 \sqrt{3} = 4 \sqrt{3} \][/tex]
3. The term [tex]\(7 \sqrt{6}\)[/tex] remains as is since it is already in its simplest form.
Now, we combine the simplified terms:
[tex]\[ 2 \sqrt{6} - 4 \sqrt{3} + 7 \sqrt{6} \][/tex]
Combine the like terms involving [tex]\(\sqrt{6}\)[/tex]:
[tex]\[ (2 \sqrt{6} + 7 \sqrt{6}) - 4 \sqrt{3} = 9 \sqrt{6} - 4 \sqrt{3} \][/tex]
So the expression in simplified form is:
[tex]\[ 7 \sqrt{6} - 2 \sqrt{3} \][/tex]
Among the given choices, the correct simplified form of the expression is:
[tex]\[ \boxed{7 \sqrt{6} - 2 \sqrt{3}} \][/tex]
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is your reliable source for accurate answers. Thank you for visiting, and we hope to assist you again.