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What are the solutions to the equation [tex]x^2 - 1 = 399[/tex]?

A. [tex]x = 20[/tex] and [tex]x = -20[/tex]
B. [tex]x = 200[/tex] and [tex]x = -200[/tex]
C. [tex]x = 400[/tex] and [tex]x = -400[/tex]
D. [tex]x = \sqrt{398}[/tex] and [tex]x = -\sqrt{398}[/tex]


Sagot :

To solve the equation [tex]\(x^2 - 1 = 399\)[/tex], we need to follow these steps:

1. Isolate the quadratic term: Start by adding 1 to both sides of the equation to isolate [tex]\(x^2\)[/tex].
[tex]\[ x^2 - 1 + 1 = 399 + 1 \][/tex]
Simplifying this, we get:
[tex]\[ x^2 = 400 \][/tex]

2. Solve for [tex]\(x\)[/tex]: Take the square root of both sides of the equation to solve for [tex]\(x\)[/tex]. It is important to remember that when you take the square root of both sides, you must consider both the positive and negative roots.
[tex]\[ x = \pm \sqrt{400} \][/tex]

3. Calculate the square roots: Determine the value of [tex]\(\sqrt{400}\)[/tex].
[tex]\[ \sqrt{400} = 20 \][/tex]
Therefore, the solutions are:
[tex]\[ x = 20 \quad \text{and} \quad x = -20 \][/tex]

As a result, the solutions to the equation [tex]\(x^2 - 1 = 399\)[/tex] are:
[tex]\[ \boxed{x = 20 \text{ and } x = -20} \][/tex]

The correct answer is:
A. [tex]\(x=20\)[/tex] and [tex]\(x=-20\)[/tex]