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Sagot :
To solve for the weight of the bowling ball on the moon, we will use the formula for weight, which is:
[tex]\[ \text{Weight} = \text{mass} \times \text{gravitational acceleration} \][/tex]
Here we are given:
- The mass of the bowling ball ([tex]\( m \)[/tex]) is 6.5 kg.
- The gravitational acceleration on the moon ([tex]\( g \)[/tex]) is 1.6 m/s[tex]\(^2\)[/tex].
Plugging these values into the formula, we get:
[tex]\[ \text{Weight} = 6.5 \: \text{kg} \times 1.6 \: \text{m/s}^2 \][/tex]
Carrying out the multiplication:
[tex]\[ \text{Weight} = 6.5 \times 1.6 = 10.4 \: \text{N} \][/tex]
Therefore, the weight of the ball on the moon is 10.4 N.
Thus, the correct answer is:
D. [tex]\( 10.4 \, N \)[/tex]
[tex]\[ \text{Weight} = \text{mass} \times \text{gravitational acceleration} \][/tex]
Here we are given:
- The mass of the bowling ball ([tex]\( m \)[/tex]) is 6.5 kg.
- The gravitational acceleration on the moon ([tex]\( g \)[/tex]) is 1.6 m/s[tex]\(^2\)[/tex].
Plugging these values into the formula, we get:
[tex]\[ \text{Weight} = 6.5 \: \text{kg} \times 1.6 \: \text{m/s}^2 \][/tex]
Carrying out the multiplication:
[tex]\[ \text{Weight} = 6.5 \times 1.6 = 10.4 \: \text{N} \][/tex]
Therefore, the weight of the ball on the moon is 10.4 N.
Thus, the correct answer is:
D. [tex]\( 10.4 \, N \)[/tex]
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