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Sagot :
To solve for the base of a parallelogram given its area and height, you can use the formula for the area of a parallelogram:
[tex]\[ \text{Area} = \text{base} \times \text{height} \][/tex]
1. First, write down the given data:
- Area of the parallelogram ([tex]\( A \)[/tex]) = 160 square meters
- Height of the parallelogram ([tex]\( h \)[/tex]) = 4 meters
2. Use the area formula to isolate the base ([tex]\( b \)[/tex]):
[tex]\[ \text{base} = \frac{\text{Area}}{\text{height}} \][/tex]
3. Substitute the given values into the formula:
[tex]\[ \text{base} = \frac{160 \text{ square meters}}{4 \text{ meters}} \][/tex]
4. Perform the division:
[tex]\[ \text{base} = 40 \text{ meters} \][/tex]
Therefore, the length of the base of the parallelogram is 40 meters.
[tex]\[ \text{Area} = \text{base} \times \text{height} \][/tex]
1. First, write down the given data:
- Area of the parallelogram ([tex]\( A \)[/tex]) = 160 square meters
- Height of the parallelogram ([tex]\( h \)[/tex]) = 4 meters
2. Use the area formula to isolate the base ([tex]\( b \)[/tex]):
[tex]\[ \text{base} = \frac{\text{Area}}{\text{height}} \][/tex]
3. Substitute the given values into the formula:
[tex]\[ \text{base} = \frac{160 \text{ square meters}}{4 \text{ meters}} \][/tex]
4. Perform the division:
[tex]\[ \text{base} = 40 \text{ meters} \][/tex]
Therefore, the length of the base of the parallelogram is 40 meters.
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