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Multiply across the top of the unit conversion. What is the product of the numerator?

[tex]\[
\begin{array}{l|l}
24 \text{ moles } C_2H_6 & 7 \text{ moles } O_2 \\
\hline & 2 \text{ moles } C_2H_6
\end{array} = [?]
\][/tex]

Sagot :

GinnyAnsweridn
Sure, let's work through this step-by-step.

We are given the task to multiply across the top of a unit conversion. Let's lay out the given values:

[tex]\[ 24 \text{ moles } \text{C}_2\text{H}_6 \][/tex]

and

[tex]\[ 7 \text{ moles } \text{O}_2 \][/tex]

To find the product of these values in the numerator, we'll multiply them together:

[tex]\[ 24 \text{ moles } \text{C}_2\text{H}_6 \times 7 \text{ moles } \text{O}_2 \][/tex]

Carrying out the multiplication gives us:

[tex]\[ 24 \times 7 = 168 \][/tex]

So, the product of the numerator is:

[tex]\[ 168 \text{ moles}^{2} (\text{C}_2\text{H}_6 \cdot \text{O}_2) \][/tex]

Therefore, the final product across the numerator is [tex]\(168\)[/tex].
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